[英]Solution to insert sub-query with additional group by
我正在尝试在Oracle SQL Developer中合并两个正在运行的SQL查询,但似乎无法让sub的Group By发挥得很好。 我希望/期望看到每行的单独总计,但我得到所有行的总计。
我尝试将第二个查询添加为子查询。
查询1:
SELECT SOURCE,
sum(case when status = 'C1' then 1 else 0 end) as "C1",
sum(case when status = 'C2' then 1 else 0 end) as "C2",
sum(case when status = 'C3' then 1 else 0 end) as "C3",
sum(case when status = 'C4' then 1 else 0 end) as "C4",
sum(case when status = 'C5' then 1 else 0 end) as "C5"
FROM TABLE.req
GROUP BY SOURCE
ORDER BY SOURCE;
查询2将添加到上面:
SELECT SOURCE, COUNT(REQ.SOURCE) AS "Done in 7 Days"
FROM TABLE.req REQ
JOIN TABLE.audit AUD ON REQ.ROW_ID = AUD.RECORD_ID
WHERE (AUD.LAST_UPD - REQ.CREATED) <= 7
AND REQ.STATUS = 'Complete'
GROUP BY SOURCE;
尝试子查询:
SELECT SOURCE,
sum(case when status = 'C1' then 1 else 0 end) as "C1",
sum(case when status = 'C2' then 1 else 0 end) as "C2",
sum(case when status = 'C3' then 1 else 0 end) as "C3",
sum(case when status = 'C4' then 1 else 0 end) as "C4",
sum(case when status = 'C5' then 1 else 0 end) as "C5"
(SELECT SOURCE, COUNT(REQ.SOURCE)
FROM TABLE.req REQ
JOIN TABLE.audit AUD ON REQ.ROW_ID = AUD.RECORD_ID
WHERE (AUD.LAST_UPD - REQ.CREATED) <= 7
AND REQ.STATUS = 'Complete'
GROUP BY SOURCE) AS "Done in 7"
FROM TABLE.req
GROUP BY SOURCE
ORDER BY SOURCE;
Query 1 returns:
A 0 0 0 0 0
B 0 0 3026 26 2461
C 0 0 0 0 0
D 3 39 2 1 19
E 0 0 61156 0 79430
Query 2 returns:
A 2906
B 10
C 28
D 7
E 0
ACTUAL:Sub-Query返回附加列但是它被总计
A 0 0 0 0 0 2951
B 0 0 3026 26 2461 2951
C 0 0 0 0 0 2951
D 3 39 2 1 19 2951
E 0 0 61156 0 79430 2951
EXPECTED:子查询返回其总计的附加列BUT
A 0 0 0 0 0 2906
B 0 0 3026 26 2461 10
C 0 0 0 0 0 28
D 3 39 2 1 19 7
E 0 0 61156 0 79430 0
您似乎想要一个相关的子查询:
SELECT SOURCE,
sum(case when status = 'C1' then 1 else 0 end) as "C1",
sum(case when status = 'C2' then 1 else 0 end) as "C2",
sum(case when status = 'C3' then 1 else 0 end) as "C3",
sum(case when status = 'C4' then 1 else 0 end) as "C4",
sum(case when status = 'C5' then 1 else 0 end) as "C5",
(SELECT COUNT(*)
FROM TABLE.req REQ r2 JOIN
TABLE.audit a
ON r2.ROW_ID = a.RECORD_ID
WHERE r2.SOURCE = r.SOURCE AND
(a.LAST_UPD - r2.CREATED) <= 7 AND
r2.STATUS = 'Complete'
)
FROM TABLE.req r
GROUP BY SOURCE
ORDER BY SOURCE;
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.