Javascript范围：回调函数引发“今天不是函数”

Question

我编写了以下代码，但今天不想重复两次（今天），所以我尝试在afterAdd之后的回调函数中编写它，但是它不起作用。 为什么回调函数无法检测到它？

 <script type="text/javascript"> var today = $(document).ready( function() { var todayDate = new Date(); todayDate.setMinutes(todayDate.getMinutes() - todayDate.getTimezoneOffset()); $('input[name="purchase_date"]').val(todayDate.toISOString().slice(0,10)); }); $(".addform .repeatable").repeatable({ addTrigger: ".add", deleteTrigger: ".del", template: "#form_item", afterAdd: today }); </script> 

Answer 1

首先创建today的功能。 然后调用$(document).ready(today) ，并按照常规在代码中使用today ：

var today = function() {
  var todayDate = new Date();
  todayDate.setMinutes(todayDate.getMinutes() - todayDate.getTimezoneOffset());
  $('input[name="purchase_date"]').val(todayDate.toISOString().slice(0, 10));
};
$(document).ready(today);
$(".addform .repeatable").repeatable({
  addTrigger: ".add",
  deleteTrigger: ".del",
  template: "#form_item",
  afterAdd: today
});

Answer 2

更换

var today = $(document).ready( function() {
    var todayDate = new Date();
    todayDate.setMinutes(todayDate.getMinutes() - 
    todayDate.getTimezoneOffset());
    $('input[name="purchase_date"]').val(todayDate.toISOString().slice(0,10));
});

与

var today = function() {
    var todayDate = new Date();
    todayDate.setMinutes(todayDate.getMinutes() - 
    todayDate.getTimezoneOffset());
    $('input[name="purchase_date"]').val(todayDate.toISOString().slice(0,10));
};
$(document).ready(function() {
    today();
});

这将创建“今天”功能，并在文档准备好后运行它。