[英]I'm trying to get some data into my database. It creates the new tables but doesn't fill them
[英]How create database and tables, and fill them with data? I got error
我想在其表中创建一个数据库并用数据填充它。 为此,我编写了以下代码,但结果是错误:
<?php
$json = json_decode(file_get_contents("categories.json"), true)['categories'];
foreach ($json as $elem) {
print_r($elem);
}
$link = mysqli_connect('localhost', 'root', '');
$sql = "DROP DATABASE cats";
mysqli_query($link, $sql);
$sql = "CREATE DATABASE cats";
mysqli_query($link, $sql);
$sql = "CREATE TABLE cats.categories (id INT NOT NULL AUTO_INCREMENT, id_category INT, name VARCHAR(255), alias VARCHAR(255))";
mysqli_query($link, $sql);
$sql = "CREATE TABLE cats.category_child (id INT NOT NULL AUTO_INCREMENT, id_category INT, id_child INT)";
mysqli_query($link, $sql);
foreach ($json as $elem) {
$stmt = mysqli_prepare($link, "INSERT INTO cats.categories (id_category, name, alias) VALUES (?, ?, ?)");
mysqli_stmt_bind_param($stmt, "iss", $elem['id'], $elem['name'], $elem['alias']);
mysqli_stmt_execute($stmt);
var_dump(mysqli_error($link));
mysqli_stmt_close($stmt);
}
?>
var_dump(mysqli_error($link))
print: string(37) "Table 'cats.categories' doesn't exist"
我做错了什么?
再想一想,这不起作用:
CREATE TABLE categories (
id INT NOT NULL AUTO_INCREMENT,
id_category INT,
name VARCHAR(255),
alias VARCHAR(255)
);
我认为错误是不言自明的:
表定义不正确; 只能有一个自动列,必须将其定义为键
但是,对于学习SQL的人来说,可能并不完全清楚该怎么做。 您可以将其标记为:
CREATE TABLE categories (
id INT AUTO_INCREMENT PRIMARY KEY,
id_category INT,
name VARCHAR(255),
alias VARCHAR(255)
);
顺便说一下,使用参数的荣誉!
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