RxJava - Observable的zip列表if throw异常如何获得成功响应

Question

我试图在Android中使用rxjava2调用多个API并行。 它按照要求工作，但是如果任何api抛出异常它无法给出其他API的响应，那么有没有办法调用返回成功响应的其他API。

private fun getStoreCouponData() {

    val userObservable = repo2
        .create<StoreCouponsApi>(StoreCouponsApi::class.java!!)
        .getCoupons
        .subscribeOn(Schedulers.newThread())
        .observeOn(AndroidSchedulers.mainThread())

    val eventsObservable = repo2
        .create<StoreCouponsApi>(StoreCouponsApi::class.java!!)
        .storeInfo
        .subscribeOn(Schedulers.newThread())
        .observeOn(AndroidSchedulers.mainThread())

    val combined = Observable.zip<StoreCoupons, StoreCoupons, StoreList>(userObservable, eventsObservable,
        BiFunction<StoreCoupons, StoreCoupons, StoreList> { response1, response2 -> StoreList(response1, response2) })

    combined.subscribe(object : DefaultObserver<StoreList>() {
        override fun onNext(s: StoreList) {
            for (item in s.store!!.coupons!!) {
                System.out.println(item.store)
            }
        }


        override fun onError(e: Throwable) {
           System.out.println(e)
        }

        override fun onComplete() {

        }
    })

    println(combined)

}    

Answer 1

有一个名为onErrorResumeNext回调，当一个请求出错时，可以用它来继续进程。

val combined = Observable.zip<StoreCoupons, StoreCoupons, StoreList>(userObservable, eventsObservable,
        BiFunction<StoreCoupons, StoreCoupons, StoreList> { response1, response2 -> StoreList(response1, response2) }).onErrorResumeNext(
// you can error separately on each requests, and you can call other requests )