[英]Simple SQL Pivot query with unknown number of columns
我有这个样本数据:
Item Location
A K
A X
B W
B Z
B Y
C L
我想得到这样的结果:
Item Loc1 Loc2 Loc3
A K X
B W Z Y
C L
是否可以使用SQL Pivot运算符?
我更喜欢条件聚合:
select item,
max(case when seqnum = 1 then location end) as location_1,
max(case when seqnum = 2 then location end) as location_2,
max(case when seqnum = 3 then location end) as location_3
from (select t.*,
row_number() over (partition by loc order by loc) as seqnum
from t
) t
group by item;
下面是一种使用带有动态sql的数据透视查询语法来生成所需格式的列的方法。
首先,我使用表变量来存储列名,这是使用窗口函数生成的,该函数对项进行分区,然后在该位置进行排序,并将其与“Loc”组合以生成Loc1,Loc2等。
然后我将这些管道传输到一个变量中,该变量将形成列列表。 这是通过while循环完成的,以按顺序添加每个新列。
从那里我整理列列表以删除尾随逗号。
之后,我生成了在相关点解析列变量的sql语句。 然后我执行它生成所需的结果集。
create table #table (
item char(1),
location char(1)
);
insert #table (item, location)
values
('A', 'K'),
('A', 'X'),
('B', 'W'),
('B', 'Z'),
('B', 'Y'),
('C', 'L');
declare @pivotcols nvarchar(max)='';
declare @sql nvarchar(max)='';
declare @cols table (
colname nvarchar(150),
rowno int
);
insert @cols
select distinct '[Loc'+cast(rowno as nvarchar(10))+'],', rowno from
(
select row_number()over(partition by item order by location) as rowno,
item, location
from #table t)colgenerator;
while exists (select 1 from @cols)
begin
select top 1 @pivotcols = @pivotcols+colname from @cols order by rowno;
delete from @cols where rowno in (select top 1 rowno from @cols order by rowno);
end
select @pivotcols=substring(@pivotcols, 1, len(@pivotcols)-1);
select @sql=N'select item, '+@pivotcols+'
from (
select rowno, item, location from
(
select ''Loc''+cast(row_number()over(partition by item order by location) as nvarchar(1000)) as rowno,
item, location
from #table t)x)src
pivot (max(location) for rowno in ('+@pivotcols+')) piv;';
exec(@sql);
drop table #table;
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