对象无效，无法作为React子对象（找到：[object Promise]）

Question

我有一个渲染路径的私有路由组件，它返回Uncaught Invariant Violation: Objects are not valid as a React child (found: [object Promise])当我使用async/await调用方法时， Uncaught Invariant Violation: Objects are not valid as a React child (found: [object Promise]) 。 我需要更改什么？ 有一个checkTokenExpirationMiddlewareAdvertiser()可以验证用户的角色并呈现正确的仪表板。 似乎当我async/await用户时，诺言无法完全解决。

我试图从函数中删除async ，但后来我无法从函数中获取返回值。

const AdvertiserPrivateRoute = ({ component: Component, ...rest }) => (
  <Route
    {...rest}
    render={props => {
      console.log(rest)
      if (!loggedInUser())
        return (
          <Redirect
            to={{ pathname: '/login', state: { from: props.location } }}
          />
        );
      return checkTokenExpirationMiddlewareAdvertiser(
        () => <Component {...props} />, // success component
        () => <AdvertiserError />, // failure component
      );
    }}
  />
);

export const checkTokenExpirationMiddlewareAdvertiser = async (success, fail) => {
  const { user } = await loggedInUser();
  console.log(user)
  if (user) {
    const { token } = user;
    if (jwtDecode(token).exp < Date.now() / 1000) {
      removeUser();
      return fail();
    }
    if (user.role !== 'advertiser') return fail();
    console.log('here');
    return success();
  }
  console.log("here")
  return fail();
};

Answer 1

与loggedInUser()结合使用的async await不一致。

1. 可以将其从checkTokenExpirationMiddlewareAdvertiser删除
2. 或将其添加到AdvertiserPrivateRoute （请参见下文）

取决于loggedInUser()是否为异步函数

const AdvertiserPrivateRoute = async ({ component: Component, ...rest }) => (
  <Route
    {...rest}
    render={props => {
      console.log(rest)
      const userLoggedIn = await loggedInUser();
      if (!userLoggedIn)
        return (
          <Redirect
            to={{ pathname: '/login', state: { from: props.location } }}
          />
        );
      return checkTokenExpirationMiddlewareAdvertiser(
        () => <Component {...props} />, // success component
        () => <AdvertiserError />, // failure component
      );
    }}
  />
);