[英]Haskell IO: Couldn't match expected type `IO a0' with actual type
[英]Software Transaction Memory in Haskell: Couldn't match expected type STM a0 with actual type IO ()
我有一个定义帐户的小程序,一个提现功能并尝试从中提现。 但是,它不会编译到期,并引发以下错误:
Couldn't match expected type ‘(STM a0 -> IO a0)
-> STM () -> IO ()’
with actual type ‘IO ()’
似乎编译器无法识别从STM到IO的转换。 任何指针都很棒。
import System.IO
import Control.Concurrent.STM
type Account = TVar Int
withdraw :: Account -> Int -> STM ()
withdraw acc amount = do
bal <- readTVar acc
writeTVar acc (bal - amount)
good :: Account -> IO ()
good acc = do
hPutStr stdout "Withdrawing..."
{-hi-}atomically{-/hi-} (withdraw acc 10)
main = do
acc <- atomically (newTVar 200)
good acc
hPutStr stdout "\nDone!\n"
该{-hi-}
和{-/hi-}
注释结果“缩进”的automically
,这样的结果,你写hPutStr stdout "Withdrawing..." atomically (withdraw acc 10)
例如,如果您编写:
good :: Account -> IO ()
good acc = do
hPutStr stdout "Withdrawing..."
{-hi-} atomically (withdraw acc 10)
它工作正常,因为“噪声”( {-hi-}
注释)不会导致内联atomically
功能。
注释在语义上确实没有任何作用,但是您可以考虑将其替换为空格。
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