如何从服务获取响应的JSON

Question

大家好，我正在尝试从此服务（ http://ip-api.com ）获得响应，该响应基于ip为您提供经度和纬度：

因此，当您通过ip 55.130.54.69时，它将返回以下json：

{
    "query": "55.130.54.69",
    "status": "success",
    "continent": "North America",
    "continentCode": "NA",
    "country": "United States",
    "countryCode": "US",
    "region": "AZ",
    "regionName": "Arizona",
    "city": "Sierra Vista",
    "district": "Fort Huachuca",
    "zip": "85613",
    "lat": 31.5552,
    "lon": -110.35,
    "timezone": "America/Phoenix",
    "currency": "USD",
    "isp": "CONUS-RCAS",
    "org": "USAISC",
    "as": "AS721 DoD Network Information Center",
    "asname": "DNIC-ASBLK-00721-00726",
    "mobile": false,
    "proxy": false
}

http://ip-api.com/#55.130.54.69

因此，在我的服务中，我正在执行以下操作（我以这种获得Java中地理位置的最佳方法进行指导）：

    @POST
    @Path("/test2")
    public void test2(@Context HttpServletRequest request) {

        String ip = request.getRemoteAddr();
        System.out.println("ip: " + ip);
        //Im changing value of ip cause I have an issue with "private range" ip of my machine
        ip = "55.130.54.69";
        // This is working
        Client client = ClientBuilder.newClient();
        Response response = client.target("http://ip-api.com/json/" + ip).request(MediaType.TEXT_PLAIN_TYPE)
                .header("Accept", "application/json").get();

        System.out.println("status: " + response.getStatus()); // Printing 200 so it worked
        System.out.println("body:" + response.getEntity());
        System.out.println("metadata: " + response.getMetadata());
        System.out.println(response);
    }

因此，正如您所看到的，我试图在我的问题中获取上面的json，但我不知道如何，您能给我指路吗？

Answer 1

如果需要以纯文本格式获取json，则可以尝试下一个：

@POST
@Path("/test2")
public void test2(@Context HttpServletRequest request) {

    ...

    Response response = client.target("http://ip-api.com/json/" + ip)
        .request(MediaType.TEXT_PLAIN_TYPE)
        .header("Accept", "application/json").get();

   String json = response.readEntity(String.class);
   response.close();

   // now you can do with json whatever you want to do
}

您还可以创建一个实体类，其中字段名称与json中的值名称匹配：

public class Geolocation {
    private String query;
    private String status;
    private String continent;

    // ... rest of fields and their getters and setters      
}

然后，您可以将数据作为实体的实例读取：

@POST
@Path("/test2")
public void test2(@Context HttpServletRequest request) {

    ...

    Response response = client.target("http://ip-api.com/json/" + ip)
        .request(MediaType.TEXT_PLAIN_TYPE)
        .header("Accept", "application/json").get();

   Geolocation location = response.readEntity(Geolocation.class);
   response.close();

   // now the instance of Geolocation contains all data from the message
}

如果您对获取响应的详细信息不感兴趣，则无法直接从get()方法获取结果消息：

Geolocation location = client.target("http://ip-api.com/json/" + ip)
    .request(MediaType.TEXT_PLAIN_TYPE)
    .header("Accept", "application/json").get(Geolocation.class);

// just the same has to work for String

Answer 2

该打印什么？ System.out.println("body:" + response.getEntity()); 另外，您要使用哪些库发布？那是球衣吗？