邮递员：如何断言所有数组元素都存在于另一个数组中？

Question

我断言array1中的元素是否确实存在于array2中，下面是数组样本，

var array1 = [
        {
            "name": "appe",
            "loc": "war",
            "order": 5,
            "neck": "NO",
            "end": false
        },
        {
            "name": "con",
            "loc": "conve",
            "order": 15,
            "neck": "NO",
            "end": true
        }]

var array2 = [{"neck":"NO"
"end":true,
"loc":"conve",
"name":"con",
"order":15
}]

我试过的代码-

const lodash = require("lodash");
    for(var i = 0; i < array2.length; i++ )
    {
            tests['response json contain Data'] = lodash._.has(points, array2[i]);
            //pm.expect(array2[i]).to.be.oneOf(array1);

    }

我得到的错误-

response json contain Data | AssertionError: expected false to be truthy

---

再次尝试后编辑 2-

pm.expect(array2[i]).to.be.oneOf(array1);

错误-

AssertionError | expected { Object (name, loc, ...) } to be one of [ Array(20) ]

尝试3-

pm.expect(array1).to.deep.equal(array2);

错误-

AssertionError | expected [ Array(20) ] to deeply equal [ Array(18) ]

我做错了什么？ 我想要的是，如果array2中的任何一个元素不在array1中，它应该失败。
谢谢

Answer 1

 var array1 = [{ "name": "appe", "loc": "war", "order": 5, "neck": "NO", "end": false }, { "name": "con", "loc": "conve", "order": 15, "neck": "NO", "end": true } ] var array2 = [{ "neck": "NO", "end": true, "loc": "conve", "name": "con", "order": 15 }] array2.forEach( item => { if ( !array1.includes(item)){ throw 'doesn\\'t include' } }) 

Answer 2

我想要的是，如果array2中的任何一个元素不在array1中，它将失败

 var array1 = [{ "name": "appe", "loc": "war", "order": 5, "neck": "NO", "end": false }, { "name": "con", "loc": "conve", "order": 15, "neck": "NO", "end": true } ] var array2 = [{ "neck": "NO", "end": true, "loc": "conve", "name": "con", "order": 15 }, { "neck": "NOo", "end": true, "loc": "conve", "name": "con", "order": 15 }]; // Finds at least one object on array2 which is not in array1. // The function some finds at least one according to the // result of findIndex which is using a handler who executes // the function every. // The function every, basically, compares every key-value // between array2 and array1. let result = array2.some(o => array1.findIndex(ao => Object.entries(o).every(([key, value]) => ao[key] === value)) === -1); console.log(result); // Returns true because one element is not in array1 

Answer 3

Chai断言库默认由Postman包含在其应用程序中。 因此，您需要使用to.deep.equal 。 它将比较嵌套数组和嵌套对象。

解：

pm.test("verify two objects", function () {
  var array1 = [{
    "name": "appe",
    "loc": "war",
    "order": 5,
    "neck": "NO",
    "end": false
  },
  {
    "name": "con",
    "loc": "conve",
    "order": 15,
    "neck": "NO",
    "end": true
  }];

  var array2 = [{
    "neck": "NO",
    "end": true,
    "loc": "conve",
    "name": "con",
    "order": 15
  }, 
  {
    "neck": "NOo",
    "end": true,
    "loc": "conve",
    "name": "con",
    "order": 15
  }];

  pm.expect(array1).to.deep.equal(array2); // Failed
  pm.expect(array1).to.deep.equal(array1); // Passed

});