jQuery每个循环仅给出第一个结果

Question

我正在尝试生成要通过jQuery提交给ajax调用的数组。 这是我的HTML和JavaScript：

 //Following is the JavaScript I use to generate the variables from checked checkboxes jQuery(document).on("click", ".refno", function() { var ref = jQuery(this).data("ref"); var refindex = jQuery(this).data("refindex"); var i = 0; var tutelists = []; var tutearray = {}; jQuery('.datarefindex_' + refindex).each(function() { var subjid = jQuery(this).data("subjid"); i++; tutearray["id"] = subjid; tutearray["issuedtutes"] = jQuery("input[name=tuteset_" + refindex + "_" + subjid + "]:checked").map(function() { return this.value; }).get(); }); tutelists.push(tutearray); var tutelists = JSON.stringify(tutelists); jQuery("#responsecontainer").html(tutelists); }); 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.4/jquery.min.js"></script> <a href="javascript:void(0)" class="refno" data-refindex="1" data-ref="1105898">1105898</a> <ul> <li> <div>Title 1</div> <ul class="datarefindex_1" data-subjid="opt471821"> <li> <label class="tutebtn" for="1_opt471821_1"> <input name="tuteset_1_opt471821" data-mainrefindex="1" type="checkbox" id="1_opt471821_1" data-subj="opt471821" value="1"> 1</label> </li> <li> <label class="tutebtn" for="1_opt471821_2"> <input name="tuteset_1_opt471821" data-mainrefindex="1" type="checkbox" id="1_opt471821_2" data-subj="opt471821" value="2"> 2</label> </li> </ul> </li> <li> <div>Title 2</div> <ul class="datarefindex_1" data-subjid="opt1215754"> <li> <label class="tutebtn" for="1_opt1215754_1"> <input name="tuteset_1_opt1215754" data-mainrefindex="1" type="checkbox" id="1_opt1215754_1" data-subj="opt1215754" value="1"> 1</label> </li> <li> <label class="tutebtn" for="1_opt1215754_2"> <input name="tuteset_1_opt1215754" data-mainrefindex="1" type="checkbox" id="1_opt1215754_2" data-subj="opt1215754" value="2"> 2</label> </li> </ul> </li> <li> <div>Title 3</div> <ul class="datarefindex_1" data-subjid="opt3062581"> <li> <label class="tutebtn" for="1_opt3062581_1"> <input name="tuteset_1_opt3062581" data-mainrefindex="1" type="checkbox" id="1_opt3062581_1" data-subj="opt3062581" value="1"> 1</label> </li> <li> <label class="tutebtn" for="1_opt3062581_2"> <input name="tuteset_1_opt3062581" data-mainrefindex="1" type="checkbox" id="1_opt3062581_2" data-subj="opt3062581" value="2"> 2</label> </li> </ul> </li> </ul> <div id="responsecontainer"></div > 

我收到的结果如下（我已经选中了每个列表的前三个框）；

{"id":"opt3062581","issuedtutes1":["1","2","3"],
"issuedtutes2":["1","2","3"],
"issuedtutes3":["1","2","3"]}

然而，期望的结果如下：

{"id":"opt471821","issuedtutes":["1","2","3"]},
{"id":"opt1215754","issuedtutes":["1","2","3"]},
{"id":"opt3062581","issuedtutes":["1","2","3"]}

无法弄清楚我想念的是什么。 当我从函数中删除id部分时，这将返回{"id":"opt3062581","issuedtutes":["1","2","3"]} ，这是最后一个列表中的数据。 请帮忙。

声音列表的数量是动态的，并且不是固定的。

Answer 1

您的预期输出看起来像一个对象列表，因此tutelists应该是一个列表而不是对象。

 jQuery(document).on("click", ".refno", function() { var ref = jQuery(this).data("ref"); var refindex = jQuery(this).data("refindex"); var i = 0; var tutelists = []; jQuery('.datarefindex_' + refindex).each(function() { var subjid = jQuery(this).data("subjid"); i++; var tutearray = {}; tutearray["id"] = subjid; tutearray["issuedtutes"] = jQuery("input[name=tuteset_" + refindex + "_" + subjid + "]:checked").map(function() { return this.value; }).get(); tutelists.push(tutearray); }); var tutelists = JSON.stringify(tutelists); jQuery("#responsecontainer").html(tutelists); }); 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <a href="javascript:void(0)" class="refno" data-refindex="1" data-ref="1105898">1105898</a> <ul> <li> <div>Title 1</div> <ul class="datarefindex_1" data-subjid="opt471821"> <li> <label class="tutebtn" for="1_opt471821_1"> <input name="tuteset_1_opt471821" data-mainrefindex="1" type="checkbox" id="1_opt471821_1" data-subj="opt471821" value="1"> 1</label> </li> <li> <label class="tutebtn" for="1_opt471821_2"> <input name="tuteset_1_opt471821" data-mainrefindex="1" type="checkbox" id="1_opt471821_2" data-subj="opt471821" value="2"> 2</label> </li> </ul> </li> <li> <div>Title 2</div> <ul class="datarefindex_1" data-subjid="opt1215754"> <li> <label class="tutebtn" for="1_opt1215754_1"> <input name="tuteset_1_opt1215754" data-mainrefindex="1" type="checkbox" id="1_opt1215754_1" data-subj="opt1215754" value="1"> 1</label> </li> <li> <label class="tutebtn" for="1_opt1215754_2"> <input name="tuteset_1_opt1215754" data-mainrefindex="1" type="checkbox" id="1_opt1215754_2" data-subj="opt1215754" value="2"> 2</label> </li> </ul> </li> <li> <div>Title 3</div> <ul class="datarefindex_1" data-subjid="opt3062581"> <li> <label class="tutebtn" for="1_opt3062581_1"> <input name="tuteset_1_opt3062581" data-mainrefindex="1" type="checkbox" id="1_opt3062581_1" data-subj="opt3062581" value="1"> 1</label> </li> <li> <label class="tutebtn" for="1_opt3062581_2"> <input name="tuteset_1_opt3062581" data-mainrefindex="1" type="checkbox" id="1_opt3062581_2" data-subj="opt3062581" value="2"> 2</label> </li> </ul> </li> </ul> <div id="responsecontainer"></div > 

Answer 2

您的id值将替换为新的id值。 请尝试使用array的push()方法使其可行。

jQuery(document).on("click", ".refno", function () {
    var ref = jQuery(this).data("ref");
    var refindex = jQuery(this).data("refindex");

    var i = 0;
    var tutelists =[];
    tutelistElement = {};
    jQuery('.datarefindex_'+ refindex ).each(function(){
        var subjid = jQuery(this).data("subjid");
        i++;

        tutelistElement["id"] = subjid;
        tutelistElement["issuedtutes"+i] = jQuery("input[name=tuteset_"+refindex+"_"+subjid+"]:checked").map(function () { return this.value; }).get();

    });
    tutelists.push(tutelistElement);
    var tutelists = JSON.stringify(tutelists);

    jQuery("#responsecontainer").html(tutelists);

});