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如何在数组中包含的字符串中显示用户名

[英]How to display username in a String contained in an array

我不知道如何在第二个活动中显示上一个活动的用户名。

我尝试了很多方法,但是没有一个方法可以让我在字符串中显示用户名

这是MainActivity:

       private EditText nameField;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    nameField = findViewById(R.id.nameEditText);
    Button startButton = findViewById(R.id.startButton);
    startButton.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            String name = nameField.getText().toString();
            getusername(name);
        }
    });

}

private void getusername(String name) {
    Intent intent = new Intent(this, OneShot.class);
    Resources resources = getResources();
    String key = resources.getString(R.string.key_name);
    intent.putExtra(key, name);
    startActivity(intent);
}

这是SecondActivity:

 public static final String TAG = OneShot.class.getSimpleName();
private String name;
private int nextSentenceId = 0;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_one_shot);

    Intent intent = getIntent();
    name = intent.getStringExtra(getString(R.string.key_name));
    if (name == null || name.isEmpty()) {
        name = "Player";
    }
    Log.d(TAG, name);

    final int[] sentences = new int[]{R.string.page0, R.string.page2, R.string.page3, R.string.page4, R.string.page5 };

    Button next= findViewById(R.id.next);
    final TextView displayText= findViewById(R.id.displayText);

    next.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            final int limit = 5;
            if(nextSentenceId < sentences.length){
                displayText.setText(sentences[nextSentenceId]);
                ++nextSentenceId;
            }
        }
    });

}

这些是int []中的字符串:

     <string name="page0"> Hello %1$s </string>
<string name="page2"> Welcome into this application </string>
<string name="page3"> How are you ? </string>
<string name="page4"> How is the weather </string>
<string name="page5"> Is %1$s you\'re real name ? </string>

为什么没有在字符串句子中传递用户名,我该如何解决? 提前致谢。

更改:

  1. 数组中的字符串,以使其正确格式:

     <string name="page0">Hello %s</string> <string name="page5">Is %s your real name?</string> 
  2. 调用以根据上面的格式在TextView中设置文本:

     displayText.setText(String.format(Locale.getDefault(), getString(sencences[nextSentenceId]), name)); 

您在int数组中拥有的不是String值,而是用于链接到所述String资源的id。 您可以使用getResources().getString(R.string.yourstring)获得与ID关联的String资源(值getResources().getString(R.string.yourstring)

//So, instead of 
//displayText.setText(sentences[nextSentenceId]);

//use
displayText.setText(getResources().getString(sentences[nextSentenceId]));

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