替换出现数值的字符串 (1000000) 应采用十进制格式，如 (1,000,000.00)

Question

输入：

“HRA 1000000 和 TDA 120000 等福利”

所需的输出是：

“HRA 1,000,000.00 和 TDA 120,000.00 和其他福利”

string input = "HRA 1000000 and TDA 120000 and other benefits"; 
string[] numbers = Regex.Split(input, @"\D+");
foreach (string value in numbers)
{
    if (!string.IsNullOrEmpty(value))
    {
        string i = (value);                      
        i = String.Format("{0:n}", decimal.Parse(i, System.Globalization.NumberStyles.Any));
    }
}

Answer 1

检查我的代码我搜索字符串中的数字并将其替换为新格式

string strRegex = @"(\d+)";
Regex myRegex = new Regex(strRegex, RegexOptions.None);
string strTargetString = @"HRA 1000000 and TDA 120000 and other benefits";

foreach(Match match in myRegex.Matches(strTargetString))
{
    strTargetString = strTargetString.Replace(match.Value, 
                                 string.Format("{0:n}", decimal.Parse(match.Value, System.Globalization.NumberStyles.Any)));            
}

Answer 2

你可以这样做。 测试该value是否为小数并将其替换为原始字符串。

foreach (string value in numbers)
{
    decimal number = 0;
    decimal.TryParse(value, out number);
    if (number > 0)
    {
        input = input.Replace(value, string.Format("{0:N0}", number));
    }
}

Answer 3

String.Format("{0:0,0.00}", 12345);     // "12,345.00"

似乎是你所需要的。