[英]Adding an array as a new key-value pair
我有一个现有的数组,其中包含一系列项目的键值对:
resultsArray = [
{
parkName: "Central Park",
owner: "NYC"
},
{
parkName: "Patterson Park",
owner: "Baltimore"
}
]
我想为每个值都包含便利设施的项添加一个附加的键值对。 例如:如果中央公园包括一个狗公园,缓跑径和篮球场,帕特森公园包括一个棒球场和娱乐中心,那么在将便利设施添加到数组时,resultsArray现在看起来像:
resultsArray = [
{
parkName: "Central Park",
owner: "NYC",
amenities: "Dog Park", "Jogging Trail", "Basketball Courts"
},
{
parkName: "Patterson Park",
owner: "Baltimore",
amenities: "Baseball Fields", "Recreation Center"
}
]
我对Java语言还比较陌生,但是我已经为每个公园成功创建了一系列便利设施。 然后,我尝试如下添加每个amenityArray:
resultsArray.push({
amenities: amenityArray
});
但是,这并没有给我我想要的东西。
有人可以演示如何将amenityArray添加为每个公园的键值对吗?
对于resultsArray
每个对象,添加相应的便利性。
for (let i = 0; i < resultsArray.length; i++) {
resultsArray[i][i]['amenities'] = amenityArray[i];
}
更详细的版本是
for (let i = 0; i < resultsArray.length; i++) {
let result = resultsArray[i]; // i is an index
let innerResult = result[i]; // i is a key
innerResult['amenities'] = amenityArray[i];
}
迭代数组,并在内部对象中添加新的键值对。
注意:动态选择设施。
resultsArray = [{ 0: { parkName: "Central Park", owner: "NYC" } }, { 1: { parkName: "Patterson Park", owner: "Baltimore" } }]; amenities = { "0": "X Park, Y Park, Z Park", "1": "A Park, B park, C Park" }; [...resultsArray].forEach(token => { Object.keys(token).forEach(key => token[key]['amenities'] = amenities[key]); }) console.log(resultsArray);
您可以使用.forEach()
遍历数组并根据索引设置各项:
var resultsArray = [{parkName: "Central Park",owner: "NYC"},{parkName: "Patterson Park", owner: "Baltimore"}] var amenityArray = [["Dog Park", "Jogging Trail", "Basketball Courts"], ["Baseball Fields", "Recreation Center"]]; resultsArray.forEach((val, index) => {val.amenities = amenityArray[index]}) console.log(resultsArray)
您可以为此使用map
:
const newArray = resultsArray.map((item, i) => {
item[i].amenities = amenityArray[i];
return item;
});
同样,您的数组结构看起来很怪异,您应该考虑删除那些多余的嵌套对象,然后将更容易进行迭代:
resultsArray = [{
parkName: "Central Park",
owner: "NYC"
},
{
parkName: "Patterson Park",
owner: "Baltimore"
}
]
const newArray = resultsArray.map((item, i) => {
item.amenities = amenityArray[i];
return item;
});
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