[英]How to use 'group by' in sub query?
我想找到一种状态下每个驱动程序ID的百分比(在此示例中为“ isDriving”)。 这是我的数据集:
(id, duration, state, driverid) VALUES ('1', '3000', 'isDriving', 'b65');
(id, duration, state, driverid) VALUES ('1', '2500', 'isDriving', 'b65');
(id, duration, state, driverid) VALUES ('1', '500', 'isIdling', 'b65');
(id, duration, state, driverid) VALUES ('1', '5500', 'isIdling', 'b65');
(id, duration, state, driverid) VALUES ('1', '300', 'isDriving', 'b34');
(id, duration, state, driverid) VALUES ('1', '200', 'isIdling', 'b34');
(id, duration, state, driverid) VALUES ('1', '200', 'isDriving', 'b15');
(id, duration, state, driverid) VALUES ('1', '500', 'isIdling', 'b15');
我已经尝试过以下查询:
select driverid,
(sum(duration) / (select sum(duration) from table_name1 group by driverid)) * 100 as percent
from table_name1
where state='isDriving'
group by driverid
我期望这样的输出:
------------------
driverid percent |
------------------
b65 50 |
b34 60 |
b15 28.6 |
但显示给我:子查询返回的行数超过1
使用条件聚合:
select
driverid,
round(100.0 * sum(case when state = 'isDriving' then duration else 0 end) / sum(duration), 1) percent
from tablename
group by driverid;
参见演示 。
结果:
| driverid | percent |
| -------- | ------- |
| b15 | 28.6 |
| b34 | 60 |
| b65 | 47.8 |
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