[英]Oracle SQL, round greater than 'half' only
我需要将数字四舍五入并保持(.5),例如:
如果数字=(9115.7),则为(9116)
如果数字=(9115.5),则为(9115.5)
如果数字=(9115.3),则为(9115)
您可以使用case表达式重写自己的舍入逻辑:
CREATE TABLE t
AS
SELECT 9115.7 AS col FROM dual UNION ALL
SELECT 9115.5 AS col FROM dual UNION ALL
SELECT 9115.3 AS col FROM dual;
SELECT col, CASE WHEN MOD(ABS(col),1) = 0.5 THEN col ELSE ROUND(col) END
FROM t;
输出:
+---------+---------+
| COL | ROUNDED |
+---------+---------+
| 9115.7 | 9116 |
| 9115.5 | 9115.5 |
| 9115.3 | 9115 |
+---------+---------+
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