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Oracle SQL,仅舍入为“一半”以上

[英]Oracle SQL, round greater than 'half' only

我需要将数字四舍五入并保持(.5),例如:

如果数字=(9115.7),则为(9116)

如果数字=(9115.5),则为(9115.5)

如果数字=(9115.3),则为(9115)

您可以使用case表达式重写自己的舍入逻辑:

CREATE TABLE t
AS
SELECT 9115.7 AS col FROM dual UNION ALL
SELECT 9115.5 AS col FROM dual UNION ALL
SELECT 9115.3 AS col FROM dual;

SELECT col, CASE WHEN MOD(ABS(col),1) = 0.5 THEN col ELSE ROUND(col) END
FROM t;

db <> fiddle演示

输出:

+---------+---------+
|  COL    | ROUNDED |
+---------+---------+
| 9115.7  |    9116 |
| 9115.5  |  9115.5 |
| 9115.3  |    9115 |
+---------+---------+

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