[英]How to get key-value of XML in hashmap using java
我遇到一个问题,当我获取父密钥时,无法按照XML的密钥在哈希图中获取值
我正在使用的代码:
public static void main(String[] args) throws IOException {
try {
String XML="<?xml version=\"1.0\" encoding=\"UTF-8\"?>\r\n" +
"<sj0:Msg>\r\n" +
" xmlns:sj0=\"http://fakesite.org/\"\r\n" +
" xmlns:sj1=\"http://fakesite.org/ind\"\r\n" +
" <sj0:Hdr>\r\n" +
" <sj2:Option>CreateTxn</sj2:Option>\r\n" +
" <sj2:ID>172246</sj2:ID>\r\n" +
" <sj2:CountryCode>CR</sj2:CountryCode>\r\n" +
" </sj0:Hdr>\r\n" +
" <sj0:ReqDet>\r\n" +
" <sj0:MReq>\r\n" +
" <sj0:qCore>\r\n" +
" <sj1:Reference>12345678</sj1:Reference>\r\n" +
" <sj1:BrnCode>CLM</sj1:BrnCode>\r\n" +
" <sj1:Source>M1T722</sj1:Source>\r\n" +
" <sj1:TxnLegCount>2</sj1:TxnLegCount>\r\n" +
" </sj0:qCore>\r\n" +
" </sj0:MReq>\r\n" +
" <sj0:LReq>\r\n" +
" <sj0:RCore>\r\n" +
" <sj1:Amt>19.28</sj1:Amt>\r\n" +
" <sj1:Dt>2019-09-04</sj1:Dt>\r\n" +
" <sj1:Date>2019-06-27</sj1:Date>\r\n" +
" </sj0:RCore>\r\n" +
" </sj0:LReq>\r\n" +
" <sj0:LReq>\r\n" +
" <sj0:RCore>\r\n" +
" <sj1:Ind>DC</sj1:Ind>\r\n" +
" <sj1:Currency>US</sj1:Currency>\r\n" +
" <sj1:LAmt>20.28</sj1:LAmt>\r\n" +
" </sj0:RCore>\r\n" +
" </sj0:LReq>\r\n" +
" </sj0:ReqDet>\r\n" +
"</sj0:Msg>";
String XString = XML;
System.out.println(XML);
HashMap<String, String> values = new HashMap<String, String>();
Document xml = convertStringToDocument(XString);
Node user = xml.getFirstChild();
NodeList childs = user.getChildNodes();
Node child;
for (int i = 0; i < childs.getLength(); i++) {
child = childs.item(i);
System.out.println(child.getNodeName());
System.out.println(child.getNodeType());
System.out.println(child.getUserData("Source"));
System.out.println(child.getTextContent());
values.put(child.getNodeName(), child.getTextContent());
}
System.out.println("Source name");
System.out.println(values.toString());
System.out.println(values.get("Source"));
} catch (Exception ex) {
System.out.println(ex.getMessage());
}
}
private static Document convertStringToDocument(String xmlStr) {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder;
try {
builder = factory.newDocumentBuilder();
Document doc = builder.parse(new InputSource(new ByteArrayInputStream(xmlStr.getBytes("UTF-8"))));
return doc;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
输出:
{sj0:ReqDet =
12345678 CLM M1T722 2 19.28 2019-09-04 2019-06-27 DC US 20.28 , #text= , sj0:Hdr= CreateTxn 172246 CR }
我需要在haspmap键而不是ReqDet中添加Source。 我面临遍历XML的问题。 任何想法,我要去哪里错了,也请解释一下我如何获得其他键值的值,即RCore父键的Ind键。
如果此库有问题,我可以使用任何其他方法或库来完成此任务
下面的代码行带有"*"
,表示它将从XML中选择所有节点/键值
NodeList nodeList = doc.getElementsByTagName("*");
以下是适用于我的完整代码:
public static void main(String[] args) throws IOException {
String XML="YOUR XML";
HashMap<String, String> values =convertStringToDocument(XML);
System.out.println("values = "+values.get("sj1:Source"));
}
public static HashMap<String, String> convertStringToDocument(String xmlStr) {
HashMap<String, String> values = new HashMap<String, String>();
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder;
try {
builder = factory.newDocumentBuilder();
EntityResolver resolver = new EntityResolver() {
public InputSource resolveEntity(String publicId, String systemId) {
String empty = "";
ByteArrayInputStream bais = new ByteArrayInputStream(empty.getBytes());
System.out.println("resolveEntity:" + publicId + "|" + systemId);
return new InputSource(bais);
}
};
builder.setEntityResolver(resolver);
Document doc = builder.parse(new InputSource(new ByteArrayInputStream(xmlStr.getBytes("UTF-8"))));
NodeList nodeList = doc.getElementsByTagName("*");
for (int i = 0; i < nodeList.getLength(); i++) {
Node node = nodeList.item(i);
if (node.getNodeType() == Node.ELEMENT_NODE) {
values.put(node.getNodeName(), node.getTextContent());
}
}
return values;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
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