导入将数据从CSV文件导出到SQL Server DB？

Question

我正在使用Web应用程序，在其中必须执行导入导出功能。 我是新手，因此我想向您提出建议，并且在执行此功能时遇到一些问题，

首先，我有一个来自Frontend（AngularJs）的JSON数组

 [ { "MyName": "Shubham", "UserType": "Premium", "DialCode": "India", "ContactNumber": "9876543210", "EmailAddress": "Contact@Shubh.com" "Country": "India", "Notes": "Notes-Notes-Notes-Notes" }, { "MyName": "Shubham 2", "UserType": "Free Trial", "DialCode": "India", "ContactNumber": "123456789", "EmailAddress": "Contact2@Shubh.com" "Country": "India", "Notes": "Notes-Notes-Notes-Notes" } ] 

现在，我正在使用XMLbuilder将此数组转换为NodeJs中的XML

<UserXML>
    <MyName>Shubham</MyName>
    <UserType>Premium</UserType>
    <DialCode>India</DialCode>
    <ContactNumber>9876543210</ContactNumber>
    <EmailAddress>Contact@Shubh.com</EmailAddress>
    <Country>India</Country>
    <Notes>Notes-Notes-Notes-Notes</Notes>
</UserXML>
<UserXML>
    <MyName>Shubham 2</MyName>
    <UserType>Free Trial</UserType>
    <DialCode>India</DialCode>
    <ContactNumber>123456789</ContactNumber>
    <EmailAddress>Contact2@Shubh.com</EmailAddress>
    <Country>India</Country>
    <Notes>Notes2-Notes2-Notes2-Notes2</Notes>
</UserXML>

现在，我在SQL Server中使用此XML将这2条记录插入到我的用户表中，现在的问题是我在另一个表中保存了国家/地区代码和国家/地区名称。我在我的用户表中使用了外键引用，我做了一个示例代码

DROP TABLE IF EXISTS #Country
DROP TABLE IF EXISTS #user
DROP TABLE IF EXISTS #UserType


 CREATE TABLE #Country
(
    Id INT PRIMARY KEY  identity(1 ,1),
    Name VARCHAR(50) NOT NULL,
    DialCode VARCHAR(50) NOT NULL
 )
 CREATE TABLE #UserType
(
    Id INT PRIMARY KEY  identity(1 ,1),
    Name VARCHAR(50) NOT NULL
 )
 CREATE TABLE #user
(
    Id                INT PRIMARY KEY  IDENTITY(1 ,1),
    Name              VARCHAR(50) NOT NULL,
    UserTypeId        INT NOT NULL,
    DialCodeId        INT NOT NULL,
    ContactNumber     VARCHAR(50) NOT NULL,
    EmailAddress      VARCHAR(50) NOT NULL,
    CountryId         INT NOT NULL,
    Notes      VARCHAR(50) NOT NULL
   FOREIGN KEY(CountryId) REFERENCES #Country(Id),
   FOREIGN KEY(UserTypeId) REFERENCES #UserType(Id)
);



INSERT INTO #Country (Name,DialCode)
VALUES ('India','+91'), 
       ('Dubai','+971'),
       ('U.S','+1') ;
INSERT INTO #UserType (Name)
VALUES ('Premium'), 
       ('Free Trial');

情况1（工作正常），如果我只有一条记录，那么使用此处理程序就没有问题

declare @xml xml = '<UserXML>
    <Name>Shubham CASE-1</Name>
    <UserType>Premium</UserType>
    <DialCode>India</DialCode>
    <ContactNumber>9876543210</ContactNumber>
    <EmailAddress>Contact@Shubh.com</EmailAddress>
    <Country>India</Country>
    <Notes>Notes-Notes-Notes-Notes CASE-1</Notes>
</UserXML>'

现在，我必须检查国家/地区名称/用户类型，并将其与国家/地区表匹配以获取ID

DECLARE @CountryId INT 
       ,@UserType INT
SELECT @CountryId = id FROM #Country WHERE Name LIKE ''+(select U.Items.value('./DialCode[1]','NVARCHAR(200)') as DialCode FROM @xml.nodes('/UserXML') U(Items))+'%'
SELECT @UserType = id FROM #UserType WHERE Name LIKE ''+(select U.Items.value('./UserType[1]','NVARCHAR(200)') as UserType FROM @xml.nodes('/UserXML') U(Items))+'%'


INSERT INTO #user 
                SELECT 
                U.Item.query('./Name').value('.','VARCHAR(100)') Name,
                @UserType,
                @CountryId,
                U.Item.query('./ContactNumber').value('.','VARCHAR(100)') ContactNumber,
                U.Item.query('./EmailAddress').value('.','VARCHAR(100)') EmailAddress,
                @CountryId,
                U.Item.query('./Notes').value('.','VARCHAR(100)') Notes
                FROM @Xml.nodes('/UserXML') AS U(Item)

案例2（问题在这里）如果我有多个记录，那么我如何检查每个节点，然后进行联接或类似的操作，以使我的插入查询工作正常

declare @xml2 xml = '<UserXML>
    <Name>Shubham CASE-2</Name>
    <UserType>Premium</UserType>
    <DialCode>India</DialCode>
    <ContactNumber>9876543210</ContactNumber>
    <EmailAddress>Contact@Shubh.com</EmailAddress>
    <Country>India</Country>
    <Notes>Notes-Notes-Notes-Notes CASE-2</Notes>
</UserXML>
<UserXML>
    <Name>Shubham 2 CASE-2</Name>
    <UserType>Free Trial</UserType>
    <DialCode>Dubai</DialCode>
    <ContactNumber>123456789</ContactNumber>
    <EmailAddress>Contact2@Shubh.com</EmailAddress>
    <Country>Dubai</Country>
    <Notes>Notes2-Notes2-Notes2-Notes2 CASE-2</Notes>
</UserXML>'

DECLARE @CountryId2 INT 
       ,@UserType2 INT
SELECT @CountryId2 = id FROM #Country WHERE Name LIKE ''+(select U.Items.value('./DialCode[1]','NVARCHAR(200)') as DialCode FROM @xml2.nodes('/UserXML') U(Items))+'%'
SELECT @UserType2 = id FROM #UserType WHERE Name LIKE ''+(select U.Items.value('./UserType[1]','NVARCHAR(200)') as UserType FROM @xml2.nodes('/UserXML') U(Items))+'%'


INSERT INTO #user 
                SELECT 
                U.Item.query('./Name').value('.','VARCHAR(100)') Name,
                @UserType,
                @CountryId,
                U.Item.query('./ContactNumber').value('.','VARCHAR(100)') ContactNumber,
--              U.Item.query('./EmailAddress').value('.','VARCHAR(100)') EmailAddress,
                @CountryId,
                U.Item.query('./Notes').value('.','VARCHAR(100)') Notes
                FROM @xml2.nodes('/UserXML') AS U(Item)

请如果您有任何建议或其他更好的方法来执行此任务，然后帮帮我，我是新来的，所以我不知道执行此任务的最佳方法

Answer 1

您可以直接读取JSON并执行JOIN

SELECT entity.*
 FROM OPENROWSET (BULK N'd:\temp\file.json', SINGLE_CLOB) as j
 CROSS APPLY OPENJSON(BulkColumn)
 WITH(
    MyName nvarchar(100)
   ,UserType nvarchar(100)
   ,DialCode nvarchar(100)
   ,ContactNumber nvarchar(100)
   ,EmailAddress nvarchar(100)
   ,Country nvarchar(100)
   ,Notes nvarchar(500)
 ) AS entity

有关导入JSON文档和OPENJSON的更多信息