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[英]How to call constructor from another class correctly and then print it as an array to console?
[英]how to print the default constructor with private variables from another class
我想打印默认的私有bloodtype
和rhfactor
,这是O+
和+
我想从另一个具有main方法的类打印它。
我已经尝试过创建新对象并打印它们,但它仍然说我正在访问一个私有变量。 当您在scanner
上输入内容时,它会打印它,但如果您输入任何内容,我想用私有变量打印构造函数!
public class blooddata {
private String bloodtype;
private String rhFactor;
blooddata(){
bloodtype = "O";
rhFactor = "+";
}
blooddata(String btx, String rhx){
this.bloodtype = btx;
this.rhFactor = rhx;
}
public String getblood (String bloodtype){
return bloodtype;
}
public String getfactor (String rhFactor){
return rhFactor;
}
public void setblood(String bloodtype){
this.bloodtype = bloodtype;
}
public void setfactor(String factor){
this.rhFactor = factor;
}
}
这是具有main方法的类
import java.util.Scanner;
public class Runblooddata {
static Scanner sc = new Scanner(System.in);
static String btx;
static String rhx;
public static void main(String[] args) {
System.out.print("Enter blood type: ");
btx = sc.nextLine();
System.out.print("Enter rhFactor: ");
rhx = sc.nextLine();
if (btx.isEmpty() || rhx.isEmpty()){
blooddata asd = new blooddata(); //this is where i am lost
}else{
blooddata bd = new blooddata();
bd.setblood(btx);
bd.setfactor(rhx);
System.out.println(bd.getblood(btx));
System.out.println(bd.getfactor(rhx));
}
}
}
吸气剂不应该有参数。
声明名称与字段相同的方法参数时,该参数会隐藏该字段。 你基本上返回你参数。
6.4.1。 阴影
在整个d范围内,名为n shadows的字段或形式参数的声明d,名称为n的任何其他变量的声明,这些变量在d出现的范围内。
public String getBlood() {
return bloodtype;
}
public String getFactor() {
return rhFactor;
}
我会帮你简化一下。
final class Example {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter blood type: ");
String btx = sc.nextLine();
System.out.print("Enter rhFactor: ");
String rhx = sc.nextLine();
BloodData data = btx.isEmpty() || rhx.isEmpty() ?
new BloodData() :
new BloodData(btx, rhx);
System.out.println(data.getBloodType());
System.out.println(data.getRhFactor());
}
}
final class BloodData {
private final String bloodType;
private final String rhFactor;
BloodData() {
this("O", "+");
}
public BloodData(String bloodType, String rhFactor) {
this.bloodType = bloodType;
this.rhFactor = rhFactor;
}
public String getBloodType() {
return bloodType;
}
public String getRhFactor() {
return rhFactor;
}
}
由于Andrew已经在您的代码中解释了设计问题,我将引导您找到您正在寻找的解决方案。
blooddata bd = new blooddata();
if (!btx.isEmpty() && !rhx.isEmpty()){
bd.setblood(btx);
bd.setfactor(rhx);
}
System.out.println(bd.getblood());
System.out.println(bd.getfactor());
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