按值将列拆分为新列 SQL

Question

我正在尝试学习 SAS 并且我想将表的不同行拆分为不同的列，以对数据进行分组。

即，

表详细

Num    Date   Type Amount    
A1  6/12/2018 Merc   5    
A2  7/3/2014  Merc   10    
A2  6/5/2014  Merc   6    
A2  6/5/2014  Cong   15
A3  5/6/2020  Cong   30   
A4  7/8/2019  Cong   6     
A3  5/6/2020  Fres   7
A4  7/8/2019  Fres   9

我想在这张桌子上进行改造

表摘要

Num    Date   Merc Cong Fres    
A1  6/12/2018  5   
A2  7/3/2014   10    
A2  6/5/2014   6    15   
A3  5/6/2020        30   7  
A4  7/8/2019        6    9     

开发了此查询，但无法正常工作。

PROC SQL;
   CREATE TABLE WORK.Summary AS 
   SELECT t1.Number, 
          t1.Date, 
          t1.Type, 
          (case when t1.Type='Mercearia' then t1.Type) as Merc,
          (case when t1.Type='Congelado' then t1.Type) as Cong,
          (case when t1.Type='Fresco' then t1.Type) as Fres,
      FROM WORK.Detailed t1
END    

提前致谢！

Answer 1

请尝试使用 PROC TRANSPOSE。 它是动态的，因此您无需提前知道类型的数量。

proc sort data=detailed; by number date;

proc transpose data=detailed out=Summary;
by number date;
id type;
var amount;
run;

Answer 2

你很亲密。 您需要聚合并修复一些其他语法：

SELECT d.Number, d.Date, 
       MAX(case when d.Type = 'Mercearia' then d.Amount end) as Merc,
       MAX(case when d.Type = 'Congelado' then d.Amount end) as Cong,
       MAX(case when d.Type = 'Fresco' then d.Amount end) as Fres
FROM WORK.Detailed d
GROUP BY d.Number, d.Date;