SQL 查询结果需要求和

Question

代码是

select customerid, count(campaignid) as T, Convert (varchar, CreatedOn,23) from customerbenefits 
where campaignid='6EDBB808-1A91-4B1D-BE1D-27EF15C5D4C7'
and createdon between '2019-09-01' and '2019-10-01'
group by customerid,CreatedOn
having count(campaignid)>1
order by createdon desc 

结果是

 --                         id            /       count  /time         
 --18655680-3B5E-4001-1984-00000000  / 12   /2019-09-30
 --18655680-3B5E-4001-1984-00000000 /  7    /    2019-09-30
 --18655680-3B5E-4001-1984-00000000 / 6    / 2019-09-30

我想要结果为

 --                         id      /             count / time     
 --  18655680-3B5E-4001-1984-00000000 / 25/ 2019-09-30

我希望它分组到时间过滤器和总计数。

如何更改我的查询？

Answer 1

使用两个级别的聚合：

select customerid, dte, sum(T)
from (select customerid, count(*) as T, convert(varchar(255), CreatedOn, 23) as dte
      from customerbenefits 
      where campaignid = '6EDBB808-1A91-4B1D-BE1D-27EF15C5D4C7' and
            createdon >= '2019-09-01' and
            createdon < '2019-10-01'
      group by customerid, CreatedOn
      having count(*) > 1
     ) t
group by customerid, dte
order by createdon desc ;

请注意，我更改了日期比较，因此 2019-10-01 的午夜不包含在 9 月的数据中。