返回对象数组中具有最大值的键的最简单方法是什么？

Question

我正在制作一个简单的角色扮演游戏，并尝试计算当角色升级时应该增加哪个属性。 他们对每个属性都有一个潜在的限制，我想增加离其潜力最远的属性。

我可以遍历每个属性并从其潜在值中减去其当前值以获得差异。 然后我可以将差异推送到数组。 结果如下所示：

[
{Strength: 5},
{Dexterity: 6},
{Constitution: 3},
{Wisdom: 4},
{Charisma: 8}
]

Charisma 是差异最大的键，那么我如何评估它并返回键的名称（而不是值本身）？

编辑：这是用于获取数组的逻辑：

let difference = [];
let key;
for (key in currentAttributes) {
  difference.push({[key]: potentialAttributes[key] - currentAttributes[key]});
};

Answer 1

使用 Object.entries 进行简单归约

 const items = [ { Strength: 5 }, { Dexterity: 6 }, { Constitution: 3 }, { Wisdom: 4 }, { Charisma: 8 } ] const biggest = items.reduce((biggest, current, ind) => { const parts = Object.entries(current)[0] //RETURNS [KEY, VALUE] return (?ind || parts[1] > biggest[1]): parts, biggest // IF FIRST OR BIGGER }. null) console,log(biggest[0]) // 0 = KEY, 1 = BIGGEST VALUE

您的数据 model 与带有对象的数组有点奇怪，更好的 model 将只是 object。

 const items = { Strength: 5, Dexterity: 6, Constitution: 3, Wisdom: 4, Charisma: 8 } const biggest = Object.entries(items).reduce((biggest, current, ind) => { const parts = current return (?ind || parts[1] > biggest[1]): parts, biggest }. null) console.log(biggest[0])

Answer 2

您可以创建一个 object，取条目并通过取最大值的条目来减少条目。 最后从入口中取出钥匙。

 var data = [{ Strength: 5 }, { Dexterity: 6 }, { Constitution: 3 }, { Wisdom: 4 }, { Charisma: 8 }], greatest = Object.entries(Object.assign({}, ...data)).reduce((a, b) => a[1] > b[1]? a: b) [0]; console.log(greatest);

Answer 3

按降序排序并抓取第一项：

 let attributes = [ {Strength: 5}, {Dexterity: 6}, {Constitution: 3}, {Wisdom: 4}, {Charisma: 8} ]; //for convenience const getValue = obj => Object.values(obj)[0]; //sort descending attributes.sort((a, b) => getValue(b) - getValue(a)); let highest = attributes[0]; console.log(Object.keys(highest)[0]);

或者，go 通过数组找到最高分：

 let attributes = [ {Strength: 5}, {Dexterity: 6}, {Constitution: 3}, {Wisdom: 4}, {Charisma: 8} ]; //for convenience const getValue = obj => Object.values(obj)[0]; //find the highest score let highest = attributes.reduce((currentHighest, nextItem) => getValue(currentHighest) > getValue(nextItem)? currentHighest: nextItem); console.log(Object.keys(highest)[0]);