如何获取嵌套值并将其链接到将列传递到材料表的字段

Question

我正在尝试创建一个表，并且我有这样的嵌套数据：

[{
  id: 24,
  name: "DANIEL TSUTOMU OBARA",
  number: "134",
  phone: "11111111111",
  rg: "4034092666",
  EmployeeStatus: {
    createdAt: "2019-08-07T14:38:52.576Z"
    description: "Documentos rejeitados"
    id: 3
    updatedAt: "2019-08-07T14:38:52.576Z"
  },
  Sector: {
    id: 2,
    name: "Controladoria"
  }
}]

并有这个结构列表：

columns: [
          { title: "Nome", field: "name" },
          { title: "CPF", field: "cpf" },
          { title: "Função", field: "FunctionId", lookup: {} },
          {
            title: "Setor",
            field: "SectorId",
            lookup: {}
          },
          {
            title: "Status",
            field: "EmployeeStatus", <------- I want to get description here
            editable: "never"
          }
        ],

然后，我需要将这些列传递到我的材料表中，如下所示：

<MaterialTable
  columns={state.columns}
  data={state.data}
  title=""
  icons={tableIcons}
  editable={{
      onRowAdd: newData => createInstructor(newData),
      onRowUpdate: async (newData, oldData) =>
        updateInstructor(newData, oldData),
      onRowDelete: oldData => deleteInstructor(oldData)
    }}
  />

那么，我怎样才能将嵌套数据访问到列字段中呢？

谢谢！

Answer 1

请找到以下解决方案。 我希望数据也有其他对象，因此找到第一个 object 和可用的密钥。

 let data = [{ id: 24, name: "DANIEL TSUTOMU OBARA", number: "134", phone: "11111111111", rg: "4034092666", EmployeeStatus: { createdAt: "2019-08-07T14:38:52.576Z", description: "Documentos rejeitados", id: 3, updatedAt: "2019-08-07T14:38:52.576Z" }, Sector: { id: 2, name: "Controladoria" } }] let columns = [ { title: "Nome", field: "name" }, { title: "CPF", field: "cpf" }, { title: "Função", field: "FunctionId", lookup: {} }, { title: "Setor", field: "SectorId", lookup: {} }, { title: "Status", field: "EmployeeStatus", editable: "never" } ]; let columnToUpdate = columns.find(obj => obj.title==="Status"); //find the column in columns array let desc = data.find(obj => Object.keys(obj).includes('EmployeeStatus')).EmployeeStatus.description; // get description columnToUpdate.field = desc; // mutate the object console.log(columns);

Answer 2

我只是决定暂时使用查找功能并以这种方式解决。

const [state, setState] = useState({
 columns: [
  { title: "ID", field: "id", editable: "never" },
  { title: "Nome", field: "name" },
  { title: "CPF", field: "cpf" },
  { title: "Função", field: "FunctionId", lookup: {} }, // 3
  {
    title: "Setor",
    field: "SectorId",
    lookup: {}
  }, // 4
  {
    title: "Status",
    field: "EmployeeStatusId",
    lookup: {},
    editable: "never"
  }, // 5
]});
....
await api
  .get(`/employee-status`)
  .then(result => {
    status = formatSectors(state, result, 5);
  })
.....
const formatSectors = (state, result, position) => {
    let columns = state.columns;
    const indexColumnSector = 4;
    columns[position].lookup = result.data.rows.reduce(
      (accumulator, currentValue) => {
        accumulator[currentValue.id] =
          position === indexColumnSector
            ? currentValue.name
            : currentValue.description;
        return accumulator;
      },
      {}
    );
    return columns;
  };