Call MySql stored procedure which take 2 parameters from asp.net core 2.2 web API controller

Question

什么是调用具有 2 个参数的存储过程并返回包含 10 列和 403 条记录的结果的正确方法。

下面是我写的代码。

try
{

    string startDate = procedureResource.StartDate.ToString("yyyy-MM-dd") + " 00:00:00";
    string endDate = procedureResource.EndDate.ToString("yyyy-MM-dd") + " 23:59:59";

    var FromDate = new MySqlParameter("@FromDate", startDate);
    var ToDate = new MySqlParameter("@ToDate", endDate);
    var financial = context.Query<FinancialResource>().FromSql("EXECUTE GetChargesFromToDate @FromDate,@ToDate", FromDate, ToDate).ToList();
    return financial;


}
catch(Exception ex) { Console.Write(ex);throw ex; }

这是例外

{“您的 SQL 语法有错误；请查看与您的 MySQL 服务器版本相对应的手册，了解在 ''2019-09-28 00:00:00','2019-10-04 23: 附近使用的正确语法59:59'' 在第 1 行"}

Answer 1

尝试将 startDate 和 endDate 变量声明为 DateTime 而不是字符串。 您可能会发送 SQL 提供商不接受的日期/时间格式。

您可以尝试这样的事情（我假设 procedureResource.StartDate/EndDate 属于 DateTime 类型）：

DatetTime startDate = procedureResource.StartDate.Date;
DateTime endDate = procedureResource.EndDate.Date.Add (new TimeSpan (23, 59, 59));

Answer 2

在查询中将 EXECUTE 更改为 CALL

Answer 3

`try
        {
            var fromDate = resource.StartDate.ToString("yyyy-MM-dd") + " 00:00:00";
            var toDate = resource.EndDate.ToString("yyyy-MM-dd") + " 23:59:59";
            string connectionstring = "Server=dbwithriderinstance.crefat3b9j9c.ap-southeast-1.rds.amazonaws.com;Database=dborderstage;User=stagging_su_production_s;Password=85s2!892Stfe7";
            using (MySqlConnection con = new MySqlConnection(connectionstring))
            {
                using (MySqlCommand cmd = new MySqlCommand("GetChargesFromToDateV2", con))
                {
                    cmd.CommandType = CommandType.StoredProcedure;
                    cmd.Parameters.AddWithValue("@FromDate", fromDate);
                    cmd.Parameters.AddWithValue("@ToDate", toDate);
                    using (MySqlDataAdapter dbr = new MySqlDataAdapter(cmd))
                    {
                        DataTable dt = new DataTable();
                        dbr.Fill(dt);
                        return dt;
                    }
                }
            }
        }
        catch (Exception ex) { Console.Write(ex); throw ex; }
    }`