SQL 服务器 CTE 中基于日期的其他 ID 的总和

Question

我的样本 CTE 来自多个来源并从以下位置提取数据：

with sample_cte as 
(
    ae.spvr as col1,
    ae.startDate as start_dt,
    ae.END_DT as end_dt,
    round(ae.Scre, 2, 1) as Scre,
from 
    diff_sources ae

我有一个 CTE，它产生了一个 output，如下所示：

col1 | start_dt | end_dt | score
-----+----------+--------+-------
a    | 10-01-19 |10-02-19| 50.50
a    | 10-02-19 |10-03-19| 55.50
b    | 10-01-19 |10-02-19| 60.50
b    | 10-02-19 |10-03-19| 65.50
c    | 10-01-19 |10-02-19| 70.50
c    | 10-02-19 |10-03-19| 75.50

我正在寻找添加新列，该列根据日期获得分数总和（a 的分数总和 b 和 c，c 的 a 和 b 的总和类似）。

它的外观如下所示

col1 | start_dt | end_dt | new_sum_score_column
-----+----------+--------+----------------------------------------------
a    | 10-01-19 |10-02-19| sum of b and c on these dates = (60.50+70.50)
a    | 10-02-19 |10-03-19| sum of b and c on these dates = (65.50+75.50)
b    | 10-01-19 |10-02-19| sum of a and c on these dates = (50.50+70.50)
b    | 10-02-19 |10-03-19| sum of a and c on these dates = (55.50+75.50)
c    | 10-01-19 |10-02-19| similar logic
c    | 10-02-19 |10-03-19| 

Answer 1

假设日期参考是第一列，我认为这有效：

select t.*,
       sum(score) over (partition by start_dt) - score
from t;

那是。 . . 计算总和并减去当前值。

编辑：

如果有多个开始日期，则：

select t.*,
       (sum(score) over (partition by start_dt) - 
        sum(score) over (partition by start_dt, col1)
       )
from t;