[英]How to find the position of the highest and second highest value in an array in java
假设我们有一个包含 integer 数字的数组。 例如周长={180,50,65,78,90,5,150,2,35},我想在数组中找到最大值及其 position,在数组中找到第二个值及其 position。
public class FindTopTwo {
public static void main(String[] args) {
double perimeter[]= {180,50,65,78,90,5,150,2,35};
double megisto, megisto2;
int i;
megisto=perimeter[0];
megisto2=perimeter[0];
for (i=0;i<perimeter.length;i++) {
if (perimeter[i]>megisto) {
megisto2=megisto;
megisto=perimeter[i];}
else if (perimeter[i]>megisto2) {
megisto2=perimeter[i];
}
}
System.out.println("the first is:"+megisto+"the second highest value is "+megisto2);
}
}
当它们的值发生变化时,只需跟踪它们的索引( i
):
public static void main(String[] args) {
double perimeter[]= {180,50,65,78,90,5,150,2,35};
double megisto, megisto2;
megisto=perimeter[0];
int megistoIndex = 0;
megisto2=perimeter[0];
int megisto2Index = 0;
for (int i=0;i<perimeter.length;i++) {
if (perimeter[i]>megisto) {
megistoIndex = i;
megisto = perimeter[i];
} else if (perimeter[i] < megisto && perimeter[i] > megisto2) {
megisto2Index = i;
megisto2 = perimeter[i];
}
}
System.out.println(String.format("the first is: %d at index %d. The second highest value is %d at index %d", megisto, megistoIndex, megisto2, megisto2Index));
}
set highestIndex = -1;
set nextHighestIndex = -1;
for every element of perimiter:
if highestIndex = -1:
set highestIndex = i;
else if perimiter[i] > perimiter[highestIndex]
set nextHighestIndex = highestIndex;
set highestIndex = i;
else if perimiter[i] > perimieter[nextHighestIndex]
set nextHighestIndex = i;
如果数组不为空,则会在 perimiter[highestIndex] 中找到最大值
如果数组至少有两个不同的值,您将在 perimeter[nextHighestIndex] 中找到第二高的值
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