将多个 Arrays 合并为一个 2D Array

Question

我在这里有这个代码片段：

#define byte uint8_t

byte pins0[11] = {  0,  1,  2, 3,   4,  5,  6,  7, 63, 64, 65};
byte pins1[11] = {  8,  9, 10, 11, 12, 13, 14, 15, 60, 61, 62};
byte pins2[11] = { 16, 17, 18, 19, 20, 21, 22, 15, 60, 61, 62};
byte pins3[11] = { 23, 24, 25, 26, 27, 28, 29, 30, 60, 61, 62};
byte pins4[11] = { 31, 32, 33, 34, 35, 36, 37, 38, 60, 61, 62};
byte pins5[11] = { 39, 40, 41, 42, 43, 44, 45, 46, 60, 61, 62};

byte *segPins[6] = {&pins0,&pins1,&pins2,&pins3,&pins4,&pins5};

编译器显示错误：

src\main.cpp:15:63: error: cannot convert 'byte (*)[11] {aka unsigned char (*)[11]}' to 'byte* {aka unsigned char*}' in initialization
 byte *segPins[11] = {&pins0,&pins1,&pins2,&pins3,&pins4,&pins5};
                                                               ^
src\main.cpp:15:63: error: cannot convert 'byte (*)[11] {aka unsigned char (*)[11]}' to 'byte* {aka unsigned char*}' in initialization
src\main.cpp:15:63: error: cannot convert 'byte (*)[11] {aka unsigned char (*)[11]}' to 'byte* {aka unsigned char*}' in initialization
src\main.cpp:15:63: error: cannot convert 'byte (*)[11] {aka unsigned char (*)[11]}' to 'byte* {aka unsigned char*}' in initialization
src\main.cpp:15:63: error: cannot convert 'byte (*)[11] {aka unsigned char (*)[11]}' to 'byte* {aka unsigned char*}' in initialization
src\main.cpp:15:63: error: cannot convert 'byte (*)[11] {aka unsigned char (*)[11]}' to 'byte* {aka unsigned char*}' in initialization
*** [.pio\build\nanoatmega328\src\main.cpp.o] Error 1

在我看来， segPins是一个byte指针数组。 所以它应该通过编译器但它看到了不同？

Answer 1

你需要的是

byte *segPins[6] = {pins0,pins1,pins2,pins3,pins4,pins5};

这是因为&pins0指的是数组pins0的地址。

编辑

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