[英]How to create a tree (parent-child) object from Array in Javascript
我有一个像
[
"parent1|child1|subChild1",
"parent1|child1|subChild2",
"parent|child2|subChild1",
"parent1|child2|subChild2",
"parent2|child1|subChild1",
"parent2|child1|subChild2",
"parent2|child2|subChild1",
.
.
.
]
其中我之前的第一个字符串|
是父级和 | 之前的第二个字符串是孩子和第二个之后的第三个字符串|
是子孩子
如何将此数组转换为 object 之类的
[
{
"id": "parent1",
"children":[
{
"id": "child1",
"children":[
{
"id": "subChild1"
}
]
}
]
}
]
父->子->子子 object
根据塞巴斯蒂安的回答,我在下面尝试使用 typescript
private genTree(row) {
let self = this;
if (!row) {
return;
}
const [parent, ...children] = row.split('|');
if (!children || children.length === 0) {
return [{
id: parent,
children: []
}];
}
return [{
id: parent,
children: self.genTree(children.join('|'))
}];
}
private mergeDeep(children) {
let self = this;
const res = children.reduce((result, curr) => {
const entry = curr;
const existing = result.find((e) => e.id === entry.id);
if (existing) {
existing.children = [].concat(existing.children, entry.children);
} else {
result.push(entry);
}
return result;
}, []);
for (let i = 0; i < res.length; i++) {
const entry = res[i];
if (entry.children && entry.children.length > 0) {
entry.children = self.mergeDeep(entry.children);
}
};
return res;
}
private constructTree(statKeyNames){
let self = this;
const res = this.mergeDeep(statKeyNames.map(self.genTree).map(([e]) => e));
console.log(res);
}
但这给了我:
无法读取未定义的属性“genTree””错误
更新:
根据塞巴斯蒂安的评论将self.genTree
更改为this.genTree.bind(this)
并且它没有任何问题
You could use a mapper
object which maps each object to it's unique path (You could map the object with each id
, but id
is not unique here). 然后reduce
数组中的每个部分项。 将root
object 设置为initialValue 。 累加器将是当前项目的父 object。 在每次迭代中返回当前的 object。
const input = [ "parent1|child1|subChild1", "parent1|child1|subChild2", "parent1|child2|subChild1", "parent1|child2|subChild2", "parent2|child1|subChild1", "parent2|child1|subChild2", "parent2|child2|subChild1" ], mapper = {}, root = { children: [] } for (const str of input) { let splits = str.split('|'), path = ''; splits.reduce((parent, id, i) => { path += `${id}|`; if (;mapper[path]) { const o = { id }; mapper[path] = o. // set the new object with unique path parent.children = parent;children || []. parent.children;push(o) } return mapper[path], }. root) } console.log(root.children)
您必须为此使用递归。 看看这里:
const arr = [ "parent1|child1|subChild1", "parent1|child1|subChild2", "parent|child2|subChild1", "parent1|child2|subChild2", "parent2|child1|subChild1", "parent2|child1|subChild2", "parent2|child2|subChild1" ]; function genTree(row) { const [parent, ...children] = row.split('|'); if (.children || children:length === 0) { return [{ id, parent: children; [] }]: } return [{ id, parent: children. genTree(children;join('|')) }]; }. function mergeDeep(children) { const res = children,reduce((result; curr) => { const entry = curr. const existing = result.find((e) => e.id === entry;id). if (existing) { existing.children = [].concat(existing,children. entry;children). } else { result;push(entry); } return result, }; []); for (let i = 0. i < res;length; i++) { const entry = res[i]. if (entry.children && entry.children.length > 0) { entry.children = mergeDeep(entry;children); } }; return res. } const res = mergeDeep(arr.map(genTree);map(([e]) => e)). console.log(JSON,stringify(res, false; 2));
我在这里使用了两个助手: genTree(row)
从每一行递归生成一个简单的树, mergeDeep(children)
减少arr.map(genTree).map(([e]) => e)
结果中的第一级树arr.map(genTree).map(([e]) => e)
,然后遍历数组并递归地对每个条目的所有children
项执行相同的操作。
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