[英]Deserialize nested JSON with RestSharp Client
我想使用 REST Api 并反序列化嵌套的 JSON 响应。 我使用 json2csharp.com 创建了这些类。
JSON 消耗
{
id: 32,
name: "test supply object",
formId: 4,
sortOrder: 0,
created: 1572902163907,
creator: "jsingler",
attributes: [
{
id: 144,
attribute: {
attributeName: "Description",
attributeType: "TextArea",
id: 8
},
attributeValue: "for development testing. do not delete or use."
},
{
id: 145,
attribute: {
attributeName: "Quantity",
attributeType: "NumberLong",
id: 10
},
attributeValue: "4"
}
]
}
JSON2CSHARP.COM output
public partial class Asset
{
[JsonProperty(PropertyName = "id")]
public int id { get; set; }
[JsonProperty(PropertyName = "name")]
public string name { get; set; }
[JsonProperty(PropertyName = "formId")]
public int formId { get; set; }
[JsonProperty(PropertyName = "sortOrder")]
public int sortOrder { get; set; }
[JsonProperty(PropertyName = "created")]
public long created { get; set; }
[JsonProperty(PropertyName = "creator")]
public string creator { get; set; }
public List<Attribute> attributes { get; set; }
}
public partial class Attribute
{
[JsonProperty(PropertyName = "ida")]
public int id { get; set; }
[JsonProperty(PropertyName = "attribute")]
public List<Attribute1> attribute { get; set; }
[JsonProperty(PropertyName = "attributeValue")]
public string attributeValue { get; set; }
}
public partial class Attribute1
{
[JsonProperty(PropertyName = "attributeName")]
public string attributeName { get; set; }
[JsonProperty(PropertyName = "attributeType")]
public string attributeType { get; set; }
[JsonProperty(PropertyName = "ida1")]
public int id { get; set; }
}
消费API数据的方法
public static List<Asset> GetAllAssets()
{
var client = new RestClient("URL_USED");
var request = new RestRequest();
client.Authenticator = new HttpBasicAuthenticator("USERNAME", "PW");
var response = new RestResponse();
Task.Run(async () =>
{
response = await GetResponseContentAsync(client, request) as RestResponse;
}).Wait();
var AssetList = JsonConvert.DeserializeObject<List<Asset>>(response.Content);
return AssetList;
}
这总是错误: An unhandled exception occurred while processing the request. JsonSerializationException: Cannot deserialize the current JSON object (eg {"name":"value"}) into type 'System.Collections.Generic.List`1[PVF_Web.Models.Attribute1]' because the type requires a JSON array (eg [1,2,3]) to deserialize correctly. To fix this error either change the JSON to a JSON array (eg [1,2,3]) or change the deserialized type so that it is a normal .NET type (eg not a primitive type like integer, not a collection type like an array or List<T>) that can be deserialized from a JSON object. JsonObjectAttribute can also be added to the type to force it to deserialize from a JSON object. Path '[0].attributes[0].attribute.attributeName', line 1, position 158.
An unhandled exception occurred while processing the request. JsonSerializationException: Cannot deserialize the current JSON object (eg {"name":"value"}) into type 'System.Collections.Generic.List`1[PVF_Web.Models.Attribute1]' because the type requires a JSON array (eg [1,2,3]) to deserialize correctly. To fix this error either change the JSON to a JSON array (eg [1,2,3]) or change the deserialized type so that it is a normal .NET type (eg not a primitive type like integer, not a collection type like an array or List<T>) that can be deserialized from a JSON object. JsonObjectAttribute can also be added to the type to force it to deserialize from a JSON object. Path '[0].attributes[0].attribute.attributeName', line 1, position 158.
然后当我能够让 JSON 反序列化时,它不会返回属性(应用程序的真正目的)。
任何建议或想法将不胜感激。
编辑 1
[HttpPut]
public void Send(Asset newJA, int Qty)
{
var client = new RestClient("URL_TO_USE" + newJA.id + ".json");
var request = new RestRequest("", Method.PUT);
request.AddObject(newJA);
client.Authenticator = new HttpBasicAuthenticator("USERNAME", "PW");
client.ExecuteAsync(request, response => {
Console.WriteLine(response.Content);
Debug.WriteLine(response.Content);
});
}
这总是失败。
您的 JSON 无效。 Go 到https://jsonformatter.curiousconcept.com/并检查所有错误。
属性名称必须在引号之间,如果您希望它是一个数组,则需要使其成为一个数组,将方括号 - [ ] - 添加到 json 的开头和结尾。
首先确保您的 json 有效。 你可以看看这边json 属性必须在引号内"" 像这样
“ID”
.
除此之外,您的根 object 不是列表。 因此,您必须将反序列化代码更改为:
var AssetList = JsonConvert.DeserializeObject<Asset>(response.Content);
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