[英]How to check if object key exists and is not null or if it is a certain value in a foreach loop in Laravel blade?
我在blade中有一个foreach循环,我在其中循环遍历项目数组,有些项目有一个名为validation_status的附加键,它是null或object。
一个例子:
category: "Storage"
client_id: 6575
created_at: "2019-08-12 15:50:04"
created_by: 233
datasheet: null
deleted_at: null
description: "3erty"
energy_rating: 0
fk_item_type: 83
id: 369
item_model_id: 475
model_number: null
power_consumption: 3
searchable: 1
shared: 1
updated_at: "2019-11-09 17:59:04"
updated_by: 233
validated: 0
validation_status: null
vendor: null
category: "Network"
client_id: 6575
created_at: "2019-07-11 16:04:56"
created_by: 233
datasheet: null
deleted_at: null
description: "2we5"
energy_rating: 0
fk_item_type: 83
id: 357
item_model_id: 470
model_number: null
power_consumption: 55
searchable: 1
shared: 1
updated_at: "2019-11-07 10:29:57"
updated_by: 233
validated: 0
validation_status:
created_at: "2019-11-07 16:08:49"
id: 2
item_id: 357
item_type: "IT_Analysis"
message: null
name: "pending"
updated_at: "2019-11-07 16:08:49"
__proto__: Object
vendor: null
如果首先存在validation_status并且其名为name的键是某个值(例如“待定”),我想做一些事情。 我怎样才能在刀片中做到这一点?
这是我的尝试,现在else 条件被执行为true ,所以我的if 条件有问题:
<p>
@if($item->validation_status && $item->validation_status !== null)
@if($item->validation_status->name === "pending" )
<?php echo link_to('admin/items/' . $item->id . '/validation-status' . $item->validation_status->id . '/complete', 'Validate', array('class' => 'btn btn-primary w-full')); ?>
<?php echo link_to('admin/items/' . $item->id . '/validation-status' . $item->validation_status->id . '/documentation-needed', 'Request documentation', array('class' => 'btn btn-primary w-full')); ?>
<?php echo link_to('admin/items/' . $item->id . '/validation-status' . $item->validation_status->id . '/reject', 'Reject', array('class' => 'btn btn-primary w-full')); ?>
@endif
@else
<?php echo Form::submit('Accept and Save!', array('class' => 'btn btn-primary w-full')); ?>
@endif
</p>
它是 object,而不是数组。
@php $check = isset($items->validation_status); @endphp
如果属性不存在或者是 null,则 isset() 将返回 false。
因此,它非常适合您的情况。
@if($check)
//Execute your code
@endif
更清晰的方法是使用 Laravel 内置助手“可选”
例如,如果关系是 null,此代码将不会抛出错误
{{ optional($this->category)->name }}
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