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[英]select all records from one table and return null values where they do not have another record in second table
[英]Select Records against all months of a given year form one table with records from second table
我的数据库中有两个表:
MembershipInstallments
(ProjectId、AllotmentId、InstallmentId、EntryDate、AmountPaid)Memberships
(ProjectId、AllotmentId、ClientId、ClientName、RegistrationNo)我想 select 客户在一年内按月付款。 以及当年年初之前支付的金额。 我想要的结果集是
假设 2019 年:
ClientName, RegistrationNumbers, PreviouslyPaidAmount (i.e. all amounts paid in 2018), AmountPaidInJuly 2019, AmountPaidInAugust2019. ..... AmountPaidIn Jun2020
其中月份是MembershipInstallments
表中的EntryDate
。
我是这样尝试的,但是对于大型数据集来说时间太长了:
SELECT
ClientName, RegistrationNo,
(SELECT ISNULL(SUM(AmountPaid),0)
FROM MembershipInstallments
WHERE ProjectId = Membership.ProjectId
AND AllotmentId = Membership.AllotmentId
AND EntryDate < @fromDate) ASPreviouslyPaid,
(SELECT ISNULL(SUM(AmountPaid), 0)
FROM MembershipInstallments
WHERE ProjectId = Membership.ProjectId
AND AllotmentId = Memberhsip.AllotmentId
AND (MONTH(EntryDate) = 7) AND (YEAR(EntryDate) = YEAR(@fromDate)) AS JulyPayment
FROM
Memberships
WHERE
ProjectId = @projectId
任何帮助将不胜感激。
标量子查询往往被严重优化。 在您的情况下(相同的连接条件),您可以简单地利用条件聚合:
SELECT ms.ClientName,ms.RegistrationNo,
Sum(CASE WHEN mi.EntryDate<@fromDate THEN mi.AmountPaid ELSE 0 end) AS PreviouslyPaid,
Sum(CASE WHEN (Month(mi.EntryDate) = 7) AND (Year(mi.EntryDate) = Year(@fromDate)) THEN mi.AmountPaid ELSE 0)
FROM Memberships AS ms
LEFT JOIN MembershipInstallments AS mi -- don't know if Outer join is really needed
ON mi.ProjectId=ms.ProjectId
AND mi.AllotmentId=ms.AllotmentId
WHERE ms.ProjectId=@projectId
您可能能够在加入之前进行聚合,即在 CTE 中以进一步提高性能:
WITH cte AS
(
SELECT
ProjectId, AllotmentId,
Sum(CASE WHEN EntryDate<@fromDate THEN AmountPaid ELSE 0 END) AS PreviouslyPaid,
Sum(CASE WHEN (Month(EntryDate) = 7) AND (Year(EntryDate) = Year(@fromDate)) THEN AmountPaid ELSE 0 END) AS JulyPayment
FROM MembershipInstallments
WHERE ProjectId=@projectId
GROUP BY ProjectId, AllotmentId
)
SELECT ms.ClientName, ms.RegistrationNo, cte.PreviouslyPaid, cte.JulyPayment
FROM Memberships AS ms
JOIN cte
ON cte.ProjectId=ms.ProjectId
AND cte.AllotmentId=ms.AllotmentId
WHERE ms.ProjectId=@projectId
在这两种情况下,请仔细检查结果是否正确(取决于这些表之间的实际关系)
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