[英]how to get data from separate tables in different columns with no repetition
我有一个表(销售)和第二个表(付款)来跟踪每个销售员向管理员的付款
CREATE TABLE `sell` (
`sell_id` int(10) NOT NULL,
`salesman_id` int(10) NOT NULL,
`total` decimal(16,2) DEFAULT '0.00',
`advance` decimal(16,2) NOT NULL DEFAULT '0.00',
`sell_date` date DEFAULT NULL
) ;
INSERT INTO `sell` (`sell_id`, `salesman_id`, `total`, `advance`, `sell_date`) VALUES
(1, 1, '2000.00', '1000.00', '2019-06-26'),
(2, 1, '5000.00', '3500.00', '2019-06-27'),
(3, 2, '3100.00', '3100.00', '2019-06-28'),
(4, 1, '500.00', '500.00', '2019-06-29'),
(5, 1, '1200.00', '1000.00', '2019-06-29');
CREATE TABLE `payment` (
`sp_id` int(10) NOT NULL,
`salesman_id` int(10) NOT NULL,
`due` decimal(16,2) DEFAULT '0.00',
`paid` decimal(16,2) NOT NULL DEFAULT '0.00',
`payment_date` date DEFAULT NULL
) ;
INSERT INTO `payment` (`sp_id`, `salesman_id`, `due`, `paid`, `payment_date`) VALUES
(1, 2, '5000.00', '4000.00', '2019-06-26'),
(2, 1, '3000.00', '2000.00', '2019-06-27'),
(3, 3, '4000.00', '4000.00', '2019-06-27'),
(4, 1, '8500.00', '5000.00', '2019-06-28'),
(5, 2, '1200.00', '1000.00', '2019-06-29');
我想按日期将两个表的结果加入到一个查询订单中,这样,销售员的日期、到期、已付款、已售出 1
+------------+----------+---------+------+---------+-------+
| date | Due | paid | Sold | Sell_id | Sp_id |
+------------+----------+---------+------+---------+-------+
| 2019-06-26 | | | 2000 | 1 | |
| 2019-06-27 | 3000 | 2000 | | | 2 |
| 2019-06-27 | | | 5000 | 2 | |
| 2019-06-28 | 8500 | 5000 | | | 4 |
| 2019-06-29 | | | 500 | 4 | |
| 2019-06-29 | | | 1200 | 5 | |
+------------+----------+---------+------+---------+--------+
我的查询是
SELECT sp.payment_date, sp.due, sp.paid, se.total, se.sell_id, sp.sp_id FROM payment sp
INNER JOIN ( SELECT sell_id, salesman_id, total, sell_date FROM sell WHERE salesman_id = 1) se ON sp.salesman_id = se.salesman_id
WHERE sp.salesman_id = 1
ORDER BY sp.payment_date , se.sell_date
我得到的结果,重复填充列中的所有空格
要获得您想要的结果,您需要一个UNION
查询,分别从sell
和payment
中选择结果,然后按date
对它们进行排序(以及是否sold
非 NULL 以获得预期数据中的确切排序):
SELECT sell_date AS date, NULL AS due, NULL AS paid,
total AS sold, sell_id, NULL AS sp_id
FROM sell
WHERE salesman_id = 1
UNION
SELECT payment_date, due, paid, NULL, NULL, sp_id
FROM payment
WHERE salesman_id = 1
ORDER BY date, COALESCE(sold, 0)
Output:
date due paid sold sell_id sp_id
2019-06-26 null null 2000 1 null
2019-06-27 3000 2000 null null 2
2019-06-27 null null 5000 2 null
2019-06-28 8500 5000 null null 4
2019-06-29 null null 500 4 null
2019-06-29 null null 1200 5 null
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