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当我将第二个表加入第一个表时的总和不正确

[英]Incorrect sum of when I join a second table to first table

我有两张桌子:

  1. 订单(id,site,orderdate,shipping_fees,amazone_fees,totalAmount,profit_loss,processing_fees)
  2. orderItemDetails (id,orderId,product_name,product_expense)

在此处输入图像描述

我写了这个查询来获取数据,但我没有得到我想要的数据。 所以请更正我的查询,以便我获得上图中的数据。

SELECT 
    o.totalshippingfees,
    o.totalamazonefees,
    o.totalorderamount,
    o.totalprofitloss,
    o.totalprocessing_fees,
    oi.totalproductexpense,
    o.site
FROM (
    SELECT 
        orderdate,
        site,
        sum(orders.shipping_fees) as totalshippingfees,
        sum(orders.amazone_fees) as totalamazonefees,
        sum(orders.totalAmount) as totalorderamount,
        sum(orders.profit_loss) as totalprofitloss,
        sum(orders.processing_fees) as totalprocessing_fees
    FROM orders
    group by site
) as o
JOIN (
    SELECT 
        site,
        sum(orderItemDetails.product_expense) as totalproductexpense,
        sum(orders.shipping_fees) as totalshippingfees,
        sum(orders.amazone_fees) as totalamazonefees,
        sum(orders.totalAmount) as totalorderamount,
        sum(orders.profit_loss) as totalprofitloss,
        sum(orders.processing_fees) as totalprocessing_fees
    from orders 
    LEFT JOIN orderItemDetails ON orders.id = orderItemDetails.orderId 
    group by site
) as oi
WHERE MONTH(o.orderdate) = '".$monthNo."' AND YEAR(o.orderdate)= '".$monthyear[1]."'

如果我对您的理解正确,您可以在orderItemDetails上使用简单的 group by site并在orders上使用 group by site并在site上加入它们。

select *
from (
    select 
      sum(shipping_fees) as totalshippingfees,
      sum(amazone_fees) as totalamazonefees,
      sum(totalAmount) as totalorderamount,
      sum(profit_loss) as totalprofitloss,
      sum(processing_fees) as totalprocessing_fees,
      site
    from orders 
    group by site
 ) d1
 join (
        select
            sum(product_expense) as totalproductexpense,
            site
        from orders o
        left join orderItemDetails od
        on o.id = od.orderId 
        group by site
      ) d2
on d1.site = d2.site

DB小提琴: https://www.db-fiddle.com/f/dkpctq1XrzB7bfsrojaZHd/2

更新:

您可以为日期过滤添加where条件,如下所示:

select *
from (
    select 
      sum(shipping_fees) as totalshippingfees,
      sum(amazone_fees) as totalamazonefees,
      sum(totalAmount) as totalorderamount,
      sum(profit_loss) as totalprofitloss,
      sum(processing_fees) as totalprocessing_fees,
      site
    from orders 
    where MONTH(orderdate) = 10 AND YEAR(orderdate) = 2019
    group by site
 ) d1
 join (
        select
            sum(product_expense) as totalproductexpense,
            site
        from orders o
        left join orderItemDetails od
        on o.id = od.orderId 
        where MONTH(o.orderdate) = 10 AND YEAR(o.orderdate) = 2019
        group by o.site
      ) d2
    on d1.site = d2.site

DB小提琴: https://www.db-fiddle.com/f/kgZbS5U1oSgPAGX34URD22/0

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