[英]Incorrect sum of when I join a second table to first table
我有两张桌子:
我写了这个查询来获取数据,但我没有得到我想要的数据。 所以请更正我的查询,以便我获得上图中的数据。
SELECT
o.totalshippingfees,
o.totalamazonefees,
o.totalorderamount,
o.totalprofitloss,
o.totalprocessing_fees,
oi.totalproductexpense,
o.site
FROM (
SELECT
orderdate,
site,
sum(orders.shipping_fees) as totalshippingfees,
sum(orders.amazone_fees) as totalamazonefees,
sum(orders.totalAmount) as totalorderamount,
sum(orders.profit_loss) as totalprofitloss,
sum(orders.processing_fees) as totalprocessing_fees
FROM orders
group by site
) as o
JOIN (
SELECT
site,
sum(orderItemDetails.product_expense) as totalproductexpense,
sum(orders.shipping_fees) as totalshippingfees,
sum(orders.amazone_fees) as totalamazonefees,
sum(orders.totalAmount) as totalorderamount,
sum(orders.profit_loss) as totalprofitloss,
sum(orders.processing_fees) as totalprocessing_fees
from orders
LEFT JOIN orderItemDetails ON orders.id = orderItemDetails.orderId
group by site
) as oi
WHERE MONTH(o.orderdate) = '".$monthNo."' AND YEAR(o.orderdate)= '".$monthyear[1]."'
如果我对您的理解正确,您可以在orderItemDetails
上使用简单的 group by site
并在orders
上使用 group by site
并在site
上加入它们。
select *
from (
select
sum(shipping_fees) as totalshippingfees,
sum(amazone_fees) as totalamazonefees,
sum(totalAmount) as totalorderamount,
sum(profit_loss) as totalprofitloss,
sum(processing_fees) as totalprocessing_fees,
site
from orders
group by site
) d1
join (
select
sum(product_expense) as totalproductexpense,
site
from orders o
left join orderItemDetails od
on o.id = od.orderId
group by site
) d2
on d1.site = d2.site
DB小提琴: https://www.db-fiddle.com/f/dkpctq1XrzB7bfsrojaZHd/2
更新:
您可以为日期过滤添加where
条件,如下所示:
select *
from (
select
sum(shipping_fees) as totalshippingfees,
sum(amazone_fees) as totalamazonefees,
sum(totalAmount) as totalorderamount,
sum(profit_loss) as totalprofitloss,
sum(processing_fees) as totalprocessing_fees,
site
from orders
where MONTH(orderdate) = 10 AND YEAR(orderdate) = 2019
group by site
) d1
join (
select
sum(product_expense) as totalproductexpense,
site
from orders o
left join orderItemDetails od
on o.id = od.orderId
where MONTH(o.orderdate) = 10 AND YEAR(o.orderdate) = 2019
group by o.site
) d2
on d1.site = d2.site
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