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Java 多线程程序(生产者和消费者)挂起..?

[英]Java multithreaded program (producer and consumer) hangs..?

我有一个 Java 中生产者和消费者示例的简单变体。 我认为它应该可以正常工作,但它挂起。 我一开始以为可能是某种形式的死锁,但是当我查看线程转储时,它似乎卡在了无限循环的中间。 无论如何,我不明白为什么程序表现得如此奇怪,想知道可能导致挂起的情况。


public class ProducerConsumer { 

    public static void main(String[] args) {
        Buffer buffer = new Buffer(7);  
        Producer producer = new Producer(buffer);
        Consumer consumer = new Consumer(buffer);

        producer.start();
        consumer.start();
    }
}

class Buffer{ 
    private char [] buffer;
    private int count = 0, in = 0, out = 0;

    private final Object object1 = new Object(); 

    Buffer(int size){
        buffer = new char[size];
    }

    public void put (char c) {
        while(count == buffer.length) ;

        synchronized(object1) { 
            System.out.println("Producing" + c + "...");
            buffer[in] = c;
            in = (in + 1) % buffer.length;
            count++;    
        }
    }

    public char get() {
        while(count == 0) ;  
        char c = buffer[out];

        synchronized(object1) {
            out = (out + 1) % buffer.length;
            count--;
            System.out.println("Consuming" + c + "...");
            }
        return c;
    }
}

class Producer extends Thread {
    private Buffer buffer;

    Producer(Buffer b){
        buffer = b;
    }

    public void run() {
        for(int i = 0; i < 10; i++) {
            buffer.put((char) ('A' + i%26 ));
        }
    }
}

class Consumer extends Thread {
    private Buffer buffer;

    Consumer(Buffer b){
        buffer = b;
    }

    public void run() {
        for(int i = 0; i < 10; i++) {
            buffer.get();
        }
    }
}

这是程序输出及其线程转储。

c:\Temp\tt>java ProducerConsumer
ProducingA...
ConsumingA...
ProducingB...
ConsumingB...
ProducingC...
ConsumingC...
ProducingD...
ConsumingD...
ProducingE...
ConsumingE...
ProducingF...
ConsumingF...
ProducingG...
ConsumingG...
ProducingH...
ConsumingH...
ProducingI...
ProducingJ...
2019-12-08 22:28:51
Full thread dump Java HotSpot(TM) 64-Bit Server VM (25.231-b11 mixed mode):

"DestroyJavaVM" #13 prio=5 os_prio=0 tid=0x0000000002761800 nid=0x3990 waiting on condition [0x0000000000000000]
   java.lang.Thread.State: RUNNABLE

"Thread-1" #12 prio=5 os_prio=0 tid=0x000000003a12a800 nid=0x36f0 runnable [0x000000003b04f000]
   java.lang.Thread.State: RUNNABLE
        at Buffer.get(ProducerConsumer.java:36)
        at Consumer.run(ProducerConsumer.java:71)

"Service Thread" #10 daemon prio=9 os_prio=0 tid=0x000000003a0ff000 nid=0x30a4 runnable [0x0000000000000000]
   java.lang.Thread.State: RUNNABLE

"C1 CompilerThread3" #9 daemon prio=9 os_prio=2 tid=0x000000003a05a000 nid=0x3890 waiting on condition [0x0000000000000000]
   java.lang.Thread.State: RUNNABLE

"C2 CompilerThread2" #8 daemon prio=9 os_prio=2 tid=0x000000003a057000 nid=0x16a4 waiting on condition [0x0000000000000000]
   java.lang.Thread.State: RUNNABLE

"C2 CompilerThread1" #7 daemon prio=9 os_prio=2 tid=0x000000003a055000 nid=0x4b4 waiting on condition [0x0000000000000000]
   java.lang.Thread.State: RUNNABLE

"C2 CompilerThread0" #6 daemon prio=9 os_prio=2 tid=0x000000003a04d800 nid=0x4160 waiting on condition [0x0000000000000000]
   java.lang.Thread.State: RUNNABLE

"Attach Listener" #5 daemon prio=5 os_prio=2 tid=0x0000000039ff9000 nid=0x1028 runnable [0x0000000000000000]
   java.lang.Thread.State: RUNNABLE

"Signal Dispatcher" #4 daemon prio=9 os_prio=2 tid=0x0000000039ff7800 nid=0x4f80 waiting on condition [0x0000000000000000]
   java.lang.Thread.State: RUNNABLE

"Finalizer" #3 daemon prio=8 os_prio=1 tid=0x0000000039fe1800 nid=0x21c in Object.wait() [0x000000003a5be000]
   java.lang.Thread.State: WAITING (on object monitor)
        at java.lang.Object.wait(Native Method)
        - waiting on <0x000000066c408ed8> (a java.lang.ref.ReferenceQueue$Lock)
        at java.lang.ref.ReferenceQueue.remove(ReferenceQueue.java:144)
        - locked <0x000000066c408ed8> (a java.lang.ref.ReferenceQueue$Lock)
        at java.lang.ref.ReferenceQueue.remove(ReferenceQueue.java:165)
        at java.lang.ref.Finalizer$FinalizerThread.run(Finalizer.java:216)

"Reference Handler" #2 daemon prio=10 os_prio=2 tid=0x0000000039fe0800 nid=0x4588 in Object.wait() [0x000000003a4bf000]
   java.lang.Thread.State: WAITING (on object monitor)
        at java.lang.Object.wait(Native Method)
        - waiting on <0x000000066c406c00> (a java.lang.ref.Reference$Lock)
        at java.lang.Object.wait(Object.java:502)
        at java.lang.ref.Reference.tryHandlePending(Reference.java:191)
        - locked <0x000000066c406c00> (a java.lang.ref.Reference$Lock)
        at java.lang.ref.Reference$ReferenceHandler.run(Reference.java:153)

"VM Thread" os_prio=2 tid=0x00000000381e9800 nid=0x5418 runnable

"GC task thread#0 (ParallelGC)" os_prio=0 tid=0x0000000002776800 nid=0x2580 runnable

"GC task thread#1 (ParallelGC)" os_prio=0 tid=0x0000000002778000 nid=0x4c98 runnable

"GC task thread#2 (ParallelGC)" os_prio=0 tid=0x000000000277a000 nid=0x560c runnable

"GC task thread#3 (ParallelGC)" os_prio=0 tid=0x000000000277b800 nid=0x3e78 runnable

"GC task thread#4 (ParallelGC)" os_prio=0 tid=0x000000000277d800 nid=0x1f24 runnable

"GC task thread#5 (ParallelGC)" os_prio=0 tid=0x0000000002780000 nid=0x5074 runnable

"GC task thread#6 (ParallelGC)" os_prio=0 tid=0x0000000002783000 nid=0x3d88 runnable

"GC task thread#7 (ParallelGC)" os_prio=0 tid=0x0000000002784000 nid=0x4d18 runnable

"VM Periodic Task Thread" os_prio=2 tid=0x000000003a11c800 nid=0x3f8c waiting on condition

JNI global references: 5

Heap
 PSYoungGen      total 304640K, used 31335K [0x000000066c400000, 0x0000000681800000, 0x00000007c0000000)
  eden space 261120K, 12% used [0x000000066c400000,0x000000066e299c00,0x000000067c300000)
  from space 43520K, 0% used [0x000000067ed80000,0x000000067ed80000,0x0000000681800000)
  to   space 43520K, 0% used [0x000000067c300000,0x000000067c300000,0x000000067ed80000)
 ParOldGen       total 696320K, used 0K [0x00000003c4c00000, 0x00000003ef400000, 0x000000066c400000)
  object space 696320K, 0% used [0x00000003c4c00000,0x00000003c4c00000,0x00000003ef400000)
 Metaspace       used 2642K, capacity 4492K, committed 4864K, reserved 1056768K
  class space    used 283K, capacity 388K, committed 512K, reserved 1048576K


任何提示将不胜感激。

当您的消费者线程在生产者线程之前开始消费时,就会出现上述情况。 您可以模拟它,但在两者之间放置一些睡眠。

Buffer buffer = new Buffer(7);
Producer producer = new Producer(buffer);
Consumer consumer = new Consumer(buffer);

consumer.start();
Thread.sleep(2000);
producer.start();

现在要修复它,您可以按照每个人的建议使用等待和通知。

我已经更新了缓冲区代码。 请检查这是否适合您。

class Buffer{
        private char [] buffer;
        private int count = 0, in = 0, out = 0;

        private final Object object1 = new Object();

        Buffer(int size){
            buffer = new char[size];
        }

        public void put (char c) throws InterruptedException {
            //while(count == buffer.length) ;

            synchronized(object1) {
                if(count == buffer.length){
                    object1.wait();
                }
                System.out.println("Producing" + c + "...");
                buffer[in] = c;
                in = (in + 1) % buffer.length;
                count++;
                object1.notify();
            }
        }

        public char get() throws InterruptedException {
            //while(count == 0) ;

            while (true){
                synchronized(object1) {
                    if(count == 0){
                        object1.wait();
                    }
                    char c = buffer[out];
                    out = (out + 1) % buffer.length;
                    count--;
                    System.out.println("Consuming" + c + "...");
                    object1.notify();
                    return c;
                }

            }

        }
    }

正如上面评论中提到的,在 while 循环中检查条件真的很危险。 解决方案之一是有两个条件 Empty 和 Full,当 Consumer 检查计数为 0 时,它等待 Empty,如果 Producer 检查计数接近限制,则它等待 Full。 然后分别在计数小于限制时Consumer唤醒Producer,当计数不为0时Producer唤醒Consumer。

为了回答你的问题,死锁是如何发生的:

消费者线程获取 count 变量的值并想要进行比较,但在比较之前,生产者线程设法填充缓冲区并进入 while 循环。 然后消费者比较他的计数为 0 并卡在循环中。 两个线程都在等待,因为消费者的计数为 0,而生产者的计数是缓冲区的大小。 我在同步时的建议是计算每种可能的情况,首先了解您可以将哪些操作视为原子操作,这意味着两个不同的线程不能同时执行。

希望我分享的知识能帮到你。

PS 我不确定你是否将算作 AtomicInteger 你会防止死锁,但至少你可以尝试这种方法。 但无论如何,请防止在多线程中使用 while 循环检查条件。

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