PHP比较两个数组并过滤数组具有特定值

Question

有两个数组。

files 数组保存文件名。

内容数组保存 html 文本。

我想检查内容中未包含的过滤器文件。

$files = ["1.jpg", "2.jpg", "3.jpg", "4.jpg", "5.jpg"];
$contents = ["<p>random text</p>", "<p>another random text</p>", "<img src='1.jpg'>"];

我试过如下，但效果不佳。

$filter = []; 
foreach ($contents as $key => $content) {

    foreach($files as $key => $file) {

        if(strpos($content, $file) == false) {
            $filter[$key] = $file;
        }               
    }
}

非常感谢。

Answer 1

看我的代码：

$files = ["1.jpg", "2.jpg", "3.jpg", "4.jpg", "5.jpg"];
$contents = ["<p>random text</p>", "<p>another random text</p>", "<img src='1.jpg'>"];

$included = [];
foreach ($contents as $content) {
    foreach ($files as $file) {
        if (strpos(strtolower($content), strtolower($file))) {
            $included[] = $file;
        }
    }
}

print_r(array_diff($files, $included));

Array ( [1] => 2.jpg [2] => 3.jpg [3] => 4.jpg [4] => 5.jpg )

Answer 2

你可以试试这个：

foreach ($contents as $content) {

    foreach($files as $file) {

        if(!strpos($content, $file)) {
            if (!in_array($file, $filter)) {
                $filter[] = $file;
            }
        } else {
            if (($key = array_search($file, $filter)) !== false) {
                unset($filter[$key]);
            }
        }
    }
}

Answer 3

尝试这个：

$files = ["1.jpg", "2.jpg", "3.jpg", "4.jpg", "5.jpg"];
$contents = ["<p>random text</p>", "<p>another random text</p>", "<img     src='1.jpg'>"];
$alltxt="";

foreach($contents as $txt)$alltxt .=$txt;
$included = [];
foreach ($files as $file) {
    if (strpos(strtolower($alltxt), strtolower($file))) {
        $included[] = $file;
    }
}
print_r(array_diff($files, $included));

结果：数组（ [1] => 2.jpg [2] => 3.jpg [3] => 4.jpg [4] => 5.jpg）