Hive sql 找出每个国家有多少普通客户

Question

我有一个名为 custtable 的表，有 3 列 custid,country,date 国家有 5 个国家：'CH'、'US'、'UK'、'FR' 和 'GE' 我希望有 elegent 查询以了解如何许多独特的 [custid] 在 5 个国家/地区。

目前，我可以使用子查询和临时表来查找重叠集，但有更简单的方法的任何建议。

这是我找出两个国家重叠的方法，然后我需要做另一个子查询

   with t1 AS
(SELECT DISTINCT [custid]
       FROM custtable
       where date>20140101
       and country='CH'),

t2 as 
 (SELECT DISTINCT [custid]
       FROM custtable
       where date>20140101
       and country='FR'),
t3 AS
(SELECT DISTINCT [custid]
       FROM custtable
       where date>20140101
       and country='US'),

t4 as 
 (SELECT DISTINCT [custid]
       FROM custtable
       where date>20140101
       and country='UK')

select count (distinct t1.custid) 
from t1 
inner join t3
on (t1.custid=t3.custid)
inner join t2
on (t1.custid=t2.custid)
inner join t4
on (t1.custid=t4.custid)

感谢您提供任何意见

Answer 1

我认为更好的方法是计算每个custid有多少个不同的国家并过滤计数 >= 5，例如，

with count_table as (
select custid, count(distinct country) as cnt
  from custtable
   where date>20140101
)
select custid, cnt
  from count_table
 where cnt >= 5

然后数你的cusid

Answer 2

SELECT COUNTRY
     , COUNT(DISTINCT CUSTID)   AS CNT
  FROM CUSTTABLE 
GROUP BY COUNTRY

Answer 3

如果您想要所有五个国家/地区的客户：

select custid
from custtable
where date > 20140101
group by custid
having count(distinct country) = 5;

如果您想要那些特定的五个国家（如您的查询所示）：

select custid
from custtable
where date > 20140101 and
      country in ('CH','US', 'UK','FR', 'GE')
group by custid
having count(distinct country) = 5;