[英]Android Application Crashes When EditText Is Entered Empty
当 EditText 为空并单击按钮时,我试图显示吐司。
单击按钮时应用程序崩溃。
我可能做错了什么? 请帮助我,因为我是移动应用程序开发的新手。 为了完成这项工作,我需要在哪里进行更改或纠正什么? 任何帮助表示赞赏。
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
import androidx.appcompat.app.AppCompatActivity;
public class EmployeeActivity extends AppCompatActivity {
EditText hourlyWage, totalRegularHours, totalOvertimeHours;
Button btnCalculate;
TextView result;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.employee_activity);
hourlyWage = findViewById(R.id.et_hourlyWage);
totalRegularHours = findViewById(R.id.et_totalRegularHours);
totalOvertimeHours = findViewById(R.id.et_totalOvertimeHours);
btnCalculate = findViewById(R.id.btnCalculate);
result = (TextView) findViewById(R.id.tv_Result);
}
// method to be called on onClick
public void calculateResult(View view) {
double regularHours = Integer.parseInt(totalRegularHours.getText().toString());
double overtimeHours;
overtimeHours = Integer.parseInt(totalOvertimeHours.getText().toString());
// check if EditText is empty
if (hourlyWage.getText().toString().trim().equals("")) {
Toast.makeText(this, "Please Enter The Value.", Toast.LENGTH_LONG).show();
}
// check if EditText is empty
else if (totalRegularHours.getText().toString().trim().equals("")) {
Toast.makeText(this, "Please Enter The Value.", Toast.LENGTH_LONG).show();
}
// check if EditText is out of range
else if (regularHours <= 0 && regularHours >= 40) {
Toast.makeText(this, "Please Enter The Value of Hours Between 0 to 40.", Toast.LENGTH_LONG).show();
}
// check if EditText is out of range
else if (overtimeHours <= 0 && overtimeHours >= 30) {
Toast.makeText(this, "Please Enter The Value of Hours Between 0 to 30.", Toast.LENGTH_LONG).show();
}
// calculates the answer
else if (regularHours >= 0 && regularHours <= 40) {
// formula for calculation
double regularWage;
regularWage = (Integer.parseInt(hourlyWage.getText().toString()) * Integer.parseInt(totalRegularHours.getText().toString())) + (Integer.parseInt(totalOvertimeHours.getText().toString()) * Integer.parseInt(hourlyWage.getText().toString()) * (1.5));
//displays the result in a TextView
result.setText(String.valueOf(regularWage));
}
}
}
您正在使用带有空字符串的Integer.parseInt
进行解析。 此外,您正在以不同的类型存储整数 - 双精度。 这是你的修复:
// method to be called on onClick
public void calculateResult(View view) {
// check if EditText is empty
if (hourlyWage.getText().toString().isEmpty()){
Toast.makeText(this, "Please Enter The Value.", Toast.LENGTH_LONG).show();
return;
}
// check if EditText is empty
if(totalRegularHours.getText().toString().isEmpty())
{
Toast.makeText(this, "Please Enter The Value.", Toast.LENGTH_LONG).show();
return;
}
int regularHours = Integer.parseInt(totalRegularHours.getText().toString());
int overtimeHours;
overtimeHours = Integer.parseInt(totalOvertimeHours.getText().toString());
// check if EditText is out of range
if (regularHours <= 0 && regularHours >= 40) {
Toast.makeText(this, "Please Enter The Value of Hours Between 0 to 40.", Toast.LENGTH_LONG).show();
}
// check if EditText is out of range
else if (overtimeHours <= 0 && overtimeHours >= 30) {
Toast.makeText(this, "Please Enter The Value of Hours Between 0 to 30.", Toast.LENGTH_LONG).show();
}
// calculates the answer
else if(regularHours >= 0 && regularHours <= 40) {
// formula for calculation
double regularWage;
regularWage = (Integer.parseInt(hourlyWage.getText().toString()) * Integer.parseInt(totalRegularHours.getText().toString())) + (Integer.parseInt(totalOvertimeHours.getText().toString()) * Integer.parseInt(hourlyWage.getText().toString()) * (1.5));
//displays the result in a TextView
result.setText(String.valueOf(regularWage));
}
}
您可以使用TextUtils
类检查EditText
是否为空,如下所示:
if(TextUtils.isEmpty(yourEditText.getText().toString())) {
Toast.makeText(this, "Edit text is empty", Toast.LENGTH_SHORT).show();
return;
}
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