在adonis中反序列化json
[英]Deserialize json in adonis
问题描述
我有这两个对象数组：
bookUnitIdInformacoes
[
{
"id": 5,
"book_id": 33,
"unit": 1,
"sequence": 1,
"description": "UNIT_01_GRAMMAR",
"qt_question": 5,
"status": false,
"user_id": 1,
"created_at": "2019-12-27 08:11:21",
"updated_at": "2019-12-30 14:54:12",
"miniature": null
},
{
"id": 6,
"book_id": 33,
"unit": 1,
"sequence": 2,
"description": "UNIT_01_VOCABULARY",
"qt_question": 5,
"status": false,
"user_id": 1,
"created_at": "2019-12-27 08:11:39",
"updated_at": "2019-12-27 08:11:39",
"miniature": null
},
{
"id": 7,
"book_id": 33,
"unit": 2,
"sequence": 1,
"description": "UNIT_02_GRAMMAR",
"qt_question": 5,
"status": false,
"user_id": 1,
"created_at": "2019-12-27 08:11:46",
"updated_at": "2019-12-27 08:11:46",
"miniature": null
},
{
"id": 8,
"book_id": 39,
"unit": 1,
"sequence": 1,
"description": "UNIT_01_GRAMMAR",
"qt_question": 5,
"status": false,
"user_id": 1,
"created_at": "2019-12-30 11:07:09",
"updated_at": "2019-12-30 15:03:50",
"miniature": null
}
]
和idioma ：
[
{
"id": 13,
"code": "ING-NOT-2019",
"description": "Inglês Noturno 2019",
"start_date": "2019-12-30T03:00:00.000Z",
"end_date": "2019-12-31T03:00:00.000Z",
"period": "Noturno",
"language": "Inglês",
"status": false,
"user_id": 1,
"created_at": "2019-12-30 10:04:47",
"updated_at": "2020-01-05 16:08:00",
"language_substring": "US"
},
{
"id": 14,
"code": "ESP-MAN-2019",
"description": "Espanhol manhã 2019",
"start_date": "2019-12-30T03:00:00.000Z",
"end_date": "2019-12-31T03:00:00.000Z",
"period": "Manhã",
"language": "Espanhol",
"status": false,
"user_id": 1,
"created_at": "2019-12-30 11:06:44",
"updated_at": "2019-12-30 11:06:44",
"language_substring": null
}
]
我通过book_id将bookUnitIdInfomacoes分组为key => value对的对象作为book_id => array of books然后，使用 [ Object.values ] 仅检索此groupedObj对象的值。 最后，我们映射idiomas并将相应的书组添加到名为quizz的新属性中。 对于给定的idioma ，我们知道它的位置idiomas感谢的第二个参数map ： i 。 我们简单地做grouped[i]来获得相应的书籍组。
编码：
const groupedObj = bookUnitIdInformacoes.reduce((grouped, info) => {
grouped[info.book_id] = grouped[info.book_id] || [];
grouped[info.book_id].push(info);
return grouped;
}, {});
const grouped = Object.values(groupedObj);
const result = idiomas.map((idioma, i) => ({
...idioma,
quizz: grouped[i]
}));
但是当我做一个返回结果时，我有这个：
[
{
"__setters__": [
"$attributes",
"$persisted",
"primaryKeyValue",
"$originalAttributes",
"$relations",
"$sideLoaded",
"$parent",
"$frozen",
"$visible",
"$hidden"
],
"$attributes": {
"id": 2,
"code": "ING-NOT-2019",
"description": "Inglês Noturno 2019",
"start_date": "2019-12-30T03:00:00.000Z",
"end_date": "2019-12-31T03:00:00.000Z",
"period": "Noturno",
"language": "Inglês",
"status": false,
"user_id": 1,
"created_at": "2019-12-30T13:04:47.000Z",
"updated_at": "2020-01-05T19:08:00.000Z",
"language_substring": "US"
},
"$persisted": true,
"$originalAttributes": {
"id": 2,
"code": "ING-NOT-2019",
"description": "Inglês Noturno 2019",
"start_date": "2019-12-30T03:00:00.000Z",
"end_date": "2019-12-31T03:00:00.000Z",
"period": "Noturno",
"language": "Inglês",
"status": false,
"user_id": 1,
"created_at": "2019-12-30T13:04:47.000Z",
"updated_at": "2020-01-05T19:08:00.000Z",
"language_substring": "US"
},
"$relations": {},
"$sideLoaded": {},
"$parent": null,
"$frozen": false,
"quizz": [
{
"id": 1,
"book_id": 1,
"unit": 1,
"sequence": 1,
"description": "UNIT_01_GRAMMAR",
"qt_question": 5,
"status": false,
"user_id": 1,
"created_at": "2019-12-27 08:11:21",
"updated_at": "2019-12-30 14:54:12",
"miniature": null
},
{
"id": 2,
"book_id": 1,
"unit": 1,
"sequence": 2,
"description": "UNIT_01_VOCABULARY",
"qt_question": 5,
"status": false,
"user_id": 1,
"created_at": "2019-12-27 08:11:39",
"updated_at": "2019-12-27 08:11:39",
"miniature": null
},
{
"id": 3,
"book_id": 1,
"unit": 2,
"sequence": 1,
"description": "UNIT_02_GRAMMAR",
"qt_question": 5,
"status": false,
"user_id": 1,
"created_at": "2019-12-27 08:11:46",
"updated_at": "2019-12-27 08:11:46",
"miniature": null
}
]
},
{
"__setters__": [
"$attributes",
"$persisted",
"primaryKeyValue",
"$originalAttributes",
"$relations",
"$sideLoaded",
"$parent",
"$frozen",
"$visible",
"$hidden"
],
"$attributes": {
"id": 3,
"code": "ESP-MAN-2019",
"description": "Espanhol manhã 2019",
"start_date": "2019-12-30T03:00:00.000Z",
"end_date": "2019-12-31T03:00:00.000Z",
"period": "Manhã",
"language": "Espanhol",
"status": false,
"user_id": 1,
"created_at": "2019-12-30T14:06:44.000Z",
"updated_at": "2019-12-30T14:06:44.000Z",
"language_substring": null
},
"$persisted": true,
"$originalAttributes": {
"id": 3,
"code": "ESP-MAN-2019",
"description": "Espanhol manhã 2019",
"start_date": "2019-12-30T03:00:00.000Z",
"end_date": "2019-12-31T03:00:00.000Z",
"period": "Manhã",
"language": "Espanhol",
"status": false,
"user_id": 1,
"created_at": "2019-12-30T14:06:44.000Z",
"updated_at": "2019-12-30T14:06:44.000Z",
"language_substring": null
},
"$relations": {},
"$sideLoaded": {},
"$parent": null,
"$frozen": false,
"quizz": [
{
"id": 4,
"book_id": 2,
"unit": 1,
"sequence": 1,
"description": "UNIT_01_GRAMMAR",
"qt_question": 5,
"status": false,
"user_id": 1,
"created_at": "2019-12-30 11:07:09",
"updated_at": "2019-12-30 15:03:50",
"miniature": null
}
]
}
]
我如何反序列化这个？ JSON.stringify(result)返回相同的 json。
1 个解决方案
解决方案1
1 2020-01-08 13:11:33
尝试这个：
const result = idiomas.map(({ $attributes }, i) => ({
...$attributes,
quizz: grouped[i]
}))
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