在 REQUEST nodejs 中返回 JSON 正文的特定变量

Question

我有这段代码对我来说效果很好，它为我带来了 JSON 格式的主体，但我不想要整个主体，我想要同一主体的特定变量，这就是代码。

 var request = require("request"); var options = { method: 'GET', url: 'https://xxx', qs: {stats: 'true', events: 'true'}, headers: { 'x-rapidapi-host': 'xx', 'x-rapidapi-key': 'xxx' } }; request(options, function (error, response, body) { if (error) throw new Error(error); console.log(body); **console.log('HOME NOMBRE: ' + body.results.id);** });

这给了我一个像这样的 JSON 文件：

 {"results":[{"id":1, "idSeason":949, "seasonName":"2020", "idHome":2069, "homeName":"MyHome", "idAway":207 ....}

我希望能够实现一些专门为我带来变量的方法，例如 homeName，以便只能使用它！

我希望我解释得很好，我期待你的帮助！

Answer 1

如果您的 API 返回一个对象数组，而您只需要一个对象属性的值数组，请使用 map...

 let results = [{ "id": 1, "idSeason": 949, "seasonName": "2020", "idHome": 2069, "homeName": "MyHome", "idAway": 207 }, { "id": 2, "idSeason": 950, "seasonName": "2021", "idHome": 2070, "homeName": "MyHome2", "idAway": 208 }] // native console.log(results.map(e => e.homeName)) // or using underscore console.log(_.pluck(results, 'homeName')) // or a smaller object console.log(results.map(e => _.pick(e, 'id', 'seasonName', 'idAway')))

 <script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.9.1/underscore-min.js"></script>

Answer 2

我认为更好的方法是使用 ES6 地图。

如果您使用对象数组

const results = [{
  "id": 1,
  "idSeason": 949,
  "seasonName": "2020",
  "idHome": 2069,
  "homeName": "MyHome",
  "idAway": 207
}, {
  "id": 2,
  "idSeason": "x",
  "seasonName": "x",
  "idHome": "x",
  "homeName": "MyHomex",
  "idAway": "x"
}]

const formattedRes = results.map(singleObject =>{
// Here redeclare the object you want, here i want to return id,seasonName and homeName
  return {
       "id": singleObject.id,
       "seasonName": singleObject.seasonName,
       "homeName": singleObject.seasonName,
        }
});
console.log(formattedRes);

结果将是

[ { id: 1, seasonName: '2020', homeName: '2020' },
  { id: 2, seasonName: 'x', homeName: 'x' } ]

更多地图 - MDN Doc