[英]Hive - find 2 characters anywhere in the string/row - RLIKE
如何获取仅分配给“USA_RBB_WA_BU”的“_WA”数据的数据? 但是,我查看的列包含包含 _WA 和 _SA (USA_CA_SAWANT) 的行
我用了,
select....
'USA_RBB_WA_BU' AS State ,
District
from TABLE where district like '%_WA%'
select ...
'USA_RBB_NSW_BU' AS State ,
District
from TABLE where district like '%_SA%'
但是我最终得到了下面的数据输出表
**state district**
USA_RBB_NSW_BU USA_CA_SAWANT
USA_RBB_WA_BU USA_CA_SAWANT
USA_RBB_NSW_BU USA_CA_SAWANT
USA_RBB_WA_BU USA_CA_SAWANT
我试过
select....
'USA_RBB_WA_BU' AS State ,
District
from TABLE where district like '_WA%'
output was was 0 results in hive
where district rlike '_WA'
将正常工作(如果字符串包含 _WA,这将返回 TRUE)
如果您希望字符串在_WA
之前和之后包含某些内容,请添加.+
(任何字符一次或多次):
where district rlike '.+_WA.+'
我猜你正在寻找逃避_
在这里。 试试下面 -
SELECT <FIELD_LIST>
'USA_RBB_WA_BU' AS State ,
District
FROM TABLE
WHERE district RLIKE '.*_WA%'
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