如何访问JS对象属性的值

Question

我正在尝试从以下 javascript 对象中提取调查值：

[{
    "id": "RJLGscviug-dg3zqAAAa",
    "name": "john",
    "room": "dormitory",
    "survey": {"Q1":"A","Q2":"B","Q3":"C"}"
}]

但是，我下面函数中的控制台日志语句返回“调查”而不是作为对象的调查值。 这是我正在使用的代码：

    const getAllSurveys = (users) => {
      var surveys = [];
      for(var user of Object.keys(users)){
        for (var userData of Object.keys(users[user])) {
          if(userData == "survey"){
            console.log(userData);
            surveys.push(userData);
          }
        }
      }
      return surveys;
    }

我怎样才能让surveys.push(userData)推送值而不是名字？

Answer 1

你必须surveys.push(users[user][userData])而不是surveys.push(userData);

Answer 2

这将起作用：

 const data = [{ "id": "RJLGscviug-dg3zqAAAa", "name": "john", "room": "dormitory", "survey": {"Q1":"A","Q2":"B","Q3":"C"} }]; const getAllSurveys = (users) => { return users.reduce((a, c) => { const userSurveys = Object.keys(c.survey).map(q => c.survey[q]); return a.concat(userSurveys); }, []); }; console.log(getAllSurveys(data));