执行 POST 请求时，无法在 XMLHttpRequest 的 node.js 版本上正确发送请求正文

Question

我正在尝试使用 NodeJS 和此处找到的 XMLHttpRequest 库向 Microsoft Oauth2.0 令牌 URL 发出 PSOT 请求。 但是，我遇到了问题，即我无法将正确的请求正文与请求一起发送。 我已经尝试从这里使用FormData ，我尝试了URLSearchParams ，并且我尝试按照我们从 GET 请求中的地址栏中知道的方式将其设置为 String 。 下面您可以看到我尝试在 GET URL 表单中执行此操作时的代码，在我推荐的部分中，您可以看到我尝试使用 FormData 代替。

var xhr = new XMLHttpRequest();
        xhr.open("POST", 'https://login.microsoftonline.com/common/oauth2/v2.0/token');

        /*var data = new FormData();
        //var data = new URLSearchParams();
        data.append('client_id', clientId);
        data.append("grant_type", "authorization_code");
        data.append("scope", "openid email profile");
        data.append("code", code);
        data.append("redirect_uri", "http://" + req.headers.host + req.url);
        data.append("client_secret", secret);
        Error message on this one: TypeError [ERR_INVALID_ARG_TYPE]: The first argument must be of type string or an instance of Buffer, ArrayBuffer, or Array or an Array-like Object. Received an instance of FormData
Same message with URLSearchParams, except it received an instance of URLSearchParams
*/

        var data = 'client_id=' + clientId;
        data += '&grant_type=authorization_code';
        data += '&scope=openid%20email%20profile';
        data += '&code=' + code;
        data += '&redirect_uri=' + encodeURIComponent("http://" + req.headers.host + req.url);
        data += '&client_secret=' + secret;
        //This one gives me an error message from Microsoft: {"error":"invalid_request","error_description":"AADSTS900144: The request body must contain the following parameter: 'grant_type'.\r\nTrace ID: ratherNotSay\r\nCorrelation ID: ratherNotSay\r\nTimestamp: 2020-02-10 10:37:36Z","error_codes":[900144],"timestamp":"2020-02-10 10:37:36Z","trace_id":"ratherNotSay","correlation_id":"ratherNotSay","error_uri":"https://login.microsoftonline.com/error?code=900144"}
//This must mean that the request body can not have been submitted in the right way.

        xhr.onreadystatechange = () => {
          if (xhr.readyState == 4) {
            console.log(xhr.status + "\n" + xhr.responseText + "\n");
          }
        };
        xhr.send(data);

Answer 1

您可以使用toString()方法将URLSearchParams实例转换为查询字符串，就像您手动构建的那样。

我不知道在node-XMLHTTPRequest版本中Content-Type标头是否默认设置为application/x-www-form-urlencoded ，但手动设置它不会有什么坏处。

const xhr = new XMLHttpRequest();
xhr.open("POST", 'https://login.microsoftonline.com/common/oauth2/v2.0/token');
xhr.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');

const data = new URLSearchParams();
data.append('client_id', clientId);
data.append("grant_type", "authorization_code");
data.append("scope", "openid email profile");
data.append("code", code);
data.append("redirect_uri", "http://" + req.headers.host + req.url);
data.append("client_secret", secret);

xhr.onreadystatechange = () => {
    if (xhr.readyState == 4) {
        console.log(xhr.status + "\n" + xhr.responseText + "\n");
    }
};

xhr.send(data.toString());