[英]How to change the CSS class of each label based on the textContent value
我有一个带有jinja
标签的 HTML 模板,可以从 JSON 对象中的列表动态创建标签。 创建该内容的循环如下。
<div class="card mb-0">
{% for turn in response %}
<div class="card-header collapsed" data-toggle="collapse" data-target="#collapse{{turn['turn_id']}}" href="#">
<a class="card-title"> {{turn['author_name']}} {{turn['date_time']}} </a>
</div>
<div id="collapse{{turn['turn_id']}}" class="card-body collapse in" >
<ul>
{% for sent in turn['list_of_sentences'] %}
<li>{{sent['text']}}</li>
{% for tag in sent['tags'] %}
<label><span class="badge" id="{{tag}}">{{ tag }}</span></label>
{% endfor %}
{% endfor %}
</ul>
</div>
{% endfor %}
</div>
我有一个 javascript 函数,它根据标签 ID 更改 css 类,因为我将标签的 textContent 分配给了 ID。
$(window).on('load', change_label_css );
function change_label_css(){
console.log("Changing CSS classes");
if (document.getElementById("OT").textContent === "OT"){
console.log(document.getElementById("OT").textContent);
document.getElementById("OT").className = "badge badge-warning";
}
if(document.getElementById("RES").textContent === "RES"){
console.log(document.getElementById("RES").textContent);
document.getElementById("RES").className = "badge badge-success";
}
if(document.getElementById("DES").textContent === "DES"){
console.log(document.getElementById("DES").textContent);
document.getElementById("DES").className = "badge badge-light";
}
if(document.getElementById("CW").textContent === "CW"){
console.log(document.getElementById("CW").textContent);
document.getElementById("CW").className = "badge badge-info";
}
if(document.getElementById("Org").textContent === "Org"){
console.log(document.getElementById("Org").textContent);
document.getElementById("Org").className = "badge badge-primary";
}
if(document.getElementById("QT").textContent === "QT"){
console.log(document.getElementById("QT").textContent);
document.getElementById("QT").className = "badge badge-primary";
}
if(document.getElementById("URL").textContent === "URL"){
console.log(document.getElementById("URL").textContent);
document.getElementById("URL").className = "badge badge-secondary";
}
else if(document.getElementById("C").textContent === "C"){
console.log(document.getElementById("C").textContent);
document.getElementById("C").className = "badge badge-dark";
}
console.log("End of changing CSS classes");
}
我不认为这是正确的逻辑,因为我有不同 ID 和相似 ID 的标签。
我想要一个关于如何遍历每个标签并根据 textContent 更改 CSS 类的建议。
您可以创建一个包含所有标签及其相应类的对象:
const labelClassMap = {
"OT": "badge badge-warning",
"RES": "badge badge-success"
...
}
然后迭代所有相关标签,因此必须设置其类的所有标签,并通过将 textContent 与您刚刚创建的地图进行比较来设置它们的类值。
for(let label of document.querySelectorAll("label" /*You may adjust the selector here*/)){
label.classList.add(...labelClassMap[label.textContent].split(" "))
}
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