android应用程序登录后不启动意图

Question

 <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.example.zomra"> <uses-permission android:name="android.permission.INTERNET"/> <application android:allowBackup="true" android:icon="@mipmap/ic_launcher" android:label="@string/app_name" android:roundIcon="@mipmap/ic_launcher_round" android:supportsRtl="true" android:theme="@style/AppTheme"> <activity android:name=".Donners"/> <activity android:name=".ThankYou"/> <activity android:name=".AddDonner"/> <activity android:name=".HomeActivity"/> <activity android:name=".RegisterActivity"/> <activity android:name=".MainActivity"> <intent-filter> <action android:name="android.intent.action.MAIN"/> <category android:name="android.intent.category.LAUNCHER"/> </intent-filter> </activity> </application> </manifest>

我的应用程序在登录成功后不会启动新的意图活动，它只是停留在当前活动中。如果我连接模拟器，它确实说登录成功，但使用我的手机它没有连接到本地主机，它说凌空错误，还有另一个问题超时，我如何从我的手机登录到我的本地主机，谢谢。

 login.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { String txtEmail = email.getText().toString(); String txtPassword = password.getText().toString(); if (TextUtils.isEmpty(txtEmail)||TextUtils.isEmpty(txtPassword)){ Toast.makeText(MainActivity.this, "All fields required", Toast.LENGTH_SHORT).show(); } else{ login(txtEmail,txtPassword); } } }); String loginStatus = sharedPreferences.getString(getResources().getString(R.string.PrefLoginState),""); if (loginStatus.equals("loggedin")){ startActivity(new Intent(getApplicationContext(),HomeActivity.class)); } } private void login(final String email, final String password){ final ProgressDialog progressDialog = new ProgressDialog(MainActivity.this); progressDialog.setCancelable(false); progressDialog.setIndeterminate(false); progressDialog.setTitle("Logging in please wait... "); progressDialog.show(); String URL = "http://10.0.2.2/login.php"; StringRequest request = new StringRequest(Request.Method.POST, URL, new Response.Listener<String>() { @Override public void onResponse(String response) { Log.d(MainActivity.class.getSimpleName(), response); if (response.equals("Login Success")){ progressDialog.dismiss(); Toast.makeText(MainActivity.this, response, Toast.LENGTH_SHORT).show(); SharedPreferences.Editor editor = sharedPreferences.edit(); if (loginState.isChecked()){ editor.putString(getResources().getString(R.string.PrefLoginState),"logged in"); } else { editor.putString(getResources().getString(R.string.PrefLoginState),"logged out"); } editor.apply(); startActivity(new Intent(MainActivity.this,HomeActivity.class)); } else { progressDialog.dismiss(); Toast.makeText(MainActivity.this, response, Toast.LENGTH_SHORT).show(); } } }, new Response.ErrorListener() { @Override public void onErrorResponse(VolleyError error) { progressDialog.dismiss(); Toast.makeText(MainActivity.this, error.toString(), Toast.LENGTH_SHORT).show(); } }){ @Override protected Map<String, String> getParams() throws AuthFailureError { HashMap<String, String> param = new HashMap<>(); param.put("email",email); param.put("password",password); return param; } }; request.setRetryPolicy(new DefaultRetryPolicy(30000, DefaultRetryPolicy.DEFAULT_MAX_RETRIES,DefaultRetryPolicy.DEFAULT_BACKOFF_MULT)); MySingleton.getmInstance(MainActivity.this).addToRequestQueue(request); } }

Answer 1

您的应用程序无法启动，因为无法从您的手机访问http://10.0.2.2/login.php 。 您需要在终端中使用ifconfig并放置从中获取的 IP 而不是变量URL ，它应该可以解决问题。