[英]Twitter Share Button for non English
嘿伙计们,首先我要感谢你们所有人阅读我的问题和你们的时间。 我有一个“推特分享”按钮,
这是html代码:
<a id="TwitterShare" target="_blank" runat="server" rel="nofollow" class="twitter"><i class="fa fa-twitter " aria-hidden="true">غرد</i></a>
这是背后的代码:
string RequestTwitter = "https://twitter.com/intent/tweet?text=";
string WebsiteURl = "https://www.MyWebsite.com/";
string Localurl = "Post/" + Postid + "/" + PostName;
string FullMineURL= WebsiteURl+Server.UrlEncode(Localurl);
string TwitterFinal = RequestTwitter + FullMineURL;
TwitterShare.Attributes.Add("href", TwitterFinal);
代码工作并获取 url,但是当我分享链接时,twitter 没有读取完整链接,这是因为它以这种方式看到的链接
اكل-الجوز-وعلاقته-وفوائده-للقلب-والامعاءhttps://Mywebsite.com/Post/3163/
我试图调试代码,但我发现代码是正确的
我跑你的代码,它工作得很好,我不认为它有问题,你的代码(也报告了这方面的一个类似的问题的问题
您可以使用URL Shortner来缩短url并在您的推文句柄中使用它,我尝试并能够分享推文
您可以登录这里,并产生GenericAccessToken 这里
用您可以生成的GenericAccessToken替换_bitlyToken
用法
确保您的页面被标记为Async 。 <%@ Page Async="true" %>
protected void Page_Load(object sender, EventArgs e)
{
RegisterAsyncTask(new PageAsyncTask(CurrentPost);
}
async Task CurrentPost()
{
...
var shortenURL = await p.ShortenAsync(FullMineURL);
string TwitterFinal = RequestTwitter + shortenURL;
TwitterShare.Attributes.Add("href", TwitterFinal);
...
}
辅助方法
public async Task<string> ShortenAsync(string longUrl)
{
//with thanks to @devfunkd - see https://stackoverflow.com/questions/31487902/nuget-package-for-bitly-to-shorten-the-links
var url = string.Format("https://api-ssl.bitly.com/v3/shorten?access_token={0}&longUrl={1}",
_bitlyToken, HttpUtility.UrlEncode(longUrl));
var request = (HttpWebRequest)WebRequest.Create(url);
try
{
var response = await request.GetResponseAsync();
using (var responseStream = response.GetResponseStream())
{
var reader = new StreamReader(responseStream, Encoding.UTF8);
var jsonResponse = JObject.Parse(await reader.ReadToEndAsync());
var statusCode = jsonResponse["status_code"].Value<int>();
if (statusCode == (int)HttpStatusCode.OK)
return jsonResponse["data"]["url"].Value<string>();
//else some sort of problem
Console.WriteLine("Bitly request returned error code {0}, status text '{1}' on longUrl = {2}",
statusCode, jsonResponse["status_txt"].Value<string>(), longUrl);
//What to do if it goes wrong? I return the original long url
return longUrl;
}
}
catch (WebException ex)
{
var errorResponse = ex.Response;
using (var responseStream = errorResponse.GetResponseStream())
{
var reader = new StreamReader(responseStream, Encoding.GetEncoding("utf-8"));
var errorText = reader.ReadToEnd();
// log errorText
Console.WriteLine("Bitly access threw an exception {0} on url {1}. Content = {2}", ex.Message, url, errorText);
}
//What to do if it goes wrong? I return the original long url
return longUrl;
}
}
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