检查字符串是否包含完全匹配

Question

我想检查一个字符串(let entry)包含与let expect完全匹配的：

 let expect = 'i was sent' let entry = 'i was sente to earth' // should return false // let entry = 'to earth i was sent' should return true // includes() using the first instance of the entry returns true if(entry.includes(expect)){ console.log('exact match') } else { console.log('no matches') }

StackOverflow 上有很多答案，但我找不到可行的解决方案。

笔记：

let expect = 'i was sent' 
let entry = 'to earth i was sent'

应该返回真

let expect = 'i was sent' 
let entry = 'i was sente to earth'

应该返回false

Answer 1

好像你在谈论匹配单词边界，可使用实现\\b的断言RegExp哪个字边界一致，所以你去：

 const escapeRegExpMatch = function(s) { return s.replace(/[-\\/\\\\^$*+?.()|[\\]{}]/g, '\\\\$&'); }; const isExactMatch = (str, match) => { return new RegExp(`\\\\b${escapeRegExpMatch(match)}\\\\b`).test(str) } const expect = 'i was sent' console.log(isExactMatch('i was sente to earth', expect)) // <~ false console.log(isExactMatch('to earth i was sent', expect)) // <~ true

希望能帮助到你 ：）

Answer 2

我尚未对此进行测试，但您需要将预期转换为字符串数组，然后检查所有项目是否都在条目字符串中。

let arr = expect.split(" ");
if (arr.every(item => entry.includes(item)) {
  console.log("match");
}
else.....