[英]get first row fo each group SQL
我有如下数据。 我想从以下数据中得到每个性别的首选
subjectID <- c("1", "2", "1", "0", "1", "0", "0", "1", "0", "2",
"0", "0", "2", "2","2","1","2","1","0","2")
gender <- c("M", "M", "F", "M", "M", "F", "M", "M", "M", "F",
"M", "F", "M", "M", "F","M", "F", "M", "F", "F")
selection <- data.frame(subjectID, gender)
subjectID <- c("1", "2", "0")
subject <- c("Maths", "Music", "English")
subjects <- data.frame(subjectID, subject)
我尝试按如下降序映射选项:
favourite <- sqldf("SELECT a.gender, b.subject, COUNT(a.subjectID) as `no of selections`
FROM selection a
JOIN subjects b
ON (a.subjectID = b.subjectID )
GROUP BY a.subjectID, a.gender
ORDER BY a.gender, `no of selections` DESC
")
但是,我想得到下表,在那里我得到每个性别的首选:
gender <- c("F", "M")
subjects <- c("Music", "Maths")
mostfav <- data.frame(gender, subjects)
如果我理解正确,您可以在 SQL 中使用窗口函数:
SELECT gs.*
FROM (SELECT s.gender, su.subject, COUNT(*) as cnt,
ROW_NUMBER() OVER (PARTITION BY s.gender ORDER BY COUNT(*) DESC) as seqnum
FROM selection s JOIN
subjects su
ON su.subjectID = s.subjectID
GROUP BY s.gender, su.subject
) gs
WHERE seqnum = 1;
如果您运行的是 MySQL 8.0,您可以在子查询中使用RANK()
按每个性别的主题计数对记录进行排名,并在外部查询中过滤每个组的最高记录(如果有最高关系, RANK()
保留他们):
SELECT gender, subject, no_of_selections
FROM (
SELECT
se.gender,
su.subject,
COUNT(*) as no_of_selections,
RANK() OVER(PARTITION BY se.gender ORDER BY COUNT(*) DESC) rn
FROM selection se
JOIN subjects su ON se.subjectID = su.subjectID
GROUP BY se.subjectID, se.gender, su.subject
) t
WHERE rn = 1
ORDER BY gender DESC
在早期版本中,在窗口功能都没有速效,一个选择是过滤器一个having
子句返回到每性别顶部数:
SELECT
se.gender,
su.subject,
COUNT(*) as no_of_selections
FROM selection se
JOIN subjects su ON se.subjectID = su.subjectID
GROUP BY se.subjectID, se.gender, su.subject
HAVING COUNT(*) = (
SELECT COUNT(*)
FROM selection se1
WHERE se1.gender = se.gender
GROUP BY se1.subjectID, se1.gender
ORDER BY COUNT(*) DESC
LIMIT 1
)
笔记:
我更改了表别名以使它们更有意义
您应该将subject
列添加到GROUP BY
子句中,以使您的查询可在 sql 模式ONLY_FULL_GROUP_MODE
下运行,默认情况下从 MySQL 5.7 开始启用
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