如何通过在嵌套对象数组中传递 id 来获取对象 JavaScript

Question

示例数据：

var data = [
{a:{id: "1",name: "alex",class: "1"}},
{a:{id: "2",name: "john",class: "2"}},
{a:{id: "3",name: "ketty",class: "3"}}
]

如果我将 id 作为 1 个结果传递：[{name:"john",class:"1"}]。

请帮我解决上述问题。

Answer 1

您可以使用_.find()获取a.id路径等于您要查找的id项目。 然后使用_.get()将项目从a属性中取出，并省略id 。

注意：这将为您提供单个项目，而不是单个项目的数组。 如果你绝对需要它，你总是可以将它包装在一个数组中。

 const { flow, find, get, omit } = _ const fn = id => flow( arr => find(arr, ['a.id', id]), // find the item which has the id item => get(item, 'a'), // extract it from a item => omit(item, 'id'), // remove the id ) const data = [{"a":{"id":"1","name":"alex","class":"1"}},{"a":{"id":"2","name":"john","class":"2"}},{"a":{"id":"3","name":"ketty","class":"3"}}] const result = fn('1')(data) console.log(result)

 <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.js"></script>

使用 lodash/fp 您可以只声明迭代对象（您希望使用的属性），因为 lodash/fp 函数是柯里化的，并且首先迭代：

 const { flow, find, get, omit } = _ const fn = id => flow( find(['a.id', id]), get('a'), omit('id'), ) const data = [{"a":{"id":"1","name":"alex","class":"1"}},{"a":{"id":"2","name":"john","class":"2"}},{"a":{"id":"3","name":"ketty","class":"3"}}] const result = fn('1')(data) console.log(result)

 <script src='https://cdn.jsdelivr.net/g/lodash@4(lodash.min.js+lodash.fp.min.js)'></script>

Answer 2

做起来真的很简单：-

var data = [
{a:{id: "1",name: "alex",class: "1"}},
{a:{id: "2",name: "john",class: "2"}},
{a:{id: "3",name: "ketty",class: "3"}}
]
let idToFind = 1;
let filtered = data.filter(f=>f['a']['id']==idToFind);