[英]Why does filterQuery not work in Elastic Search's high level REST client for JAVA?
我正在尝试创建一个对弹性搜索索引运行模糊搜索的函数。 如果我完全按照索引中的拼写指定术语,我只会得到匹配项。 如果我故意拼错了该术语中的单个字母,例如
“博克”
,我想模糊搜索仍应返回相同的匹配项,但它不返回任何匹配项。 同样,如果我用prefixQuery 或termQuery 替换fuzzyMatch,则搜索仅在给出确切拼写的情况下返回结果
“鲍勃”
为什么是这样? 我该如何解决? 哪里有解释这些方法的文档?
这是我的代码...
public void searchResults(@PathParam("index_name") String index_name) throws IOException {
RestHighLevelClient client = createHighLevelRestClient();
int numberOfSearchHitsToReturn = 100; // defaults to 10
SearchSourceBuilder sourceBuilder = new SearchSourceBuilder();
sourceBuilder.query(QueryBuilders.fuzzyQuery("firstname", "Bob"));
sourceBuilder.from(0);
sourceBuilder.size(numberOfSearchHitsToReturn);
sourceBuilder.timeout(new TimeValue(60, TimeUnit.SECONDS));
SearchRequest searchRequest = new SearchRequest(index_name).source(sourceBuilder);
SearchResponse searchResponse = client.search(searchRequest, RequestOptions.DEFAULT);
System.out.print(searchResponse);
client.close();
}
这是在 Postman 中 Get /index/_search 的结果...
{
"took": 0,
"timed_out": false,
"_shards": {
"total": 1,
"successful": 1,
"skipped": 0,
"failed": 0
},
"hits": {
"total": {
"value": 3,
"relation": "eq"
},
"max_score": 1.0,
"hits": [
{
"_index": "contacts",
"_type": "_doc",
"_id": "J1NDonABNQ4iHt4UOM4u",
"_score": 1.0,
"_source": {}
},
{
"_index": "contacts",
"_type": "_doc",
"_id": "153",
"_score": 1.0,
"_source": {
"firstname": "Bob",
"home_city": "San Diego",
"home_address": "1029 Loring Street",
"home_zip": "92109",
"contact_id": "153",
"email": "bsmith@gmail.com",
"lastname": "Smith",
"home_state": "California",
"cell_phone": "6192542981"
}
},
{
"_index": "contacts",
"_type": "_doc",
"_id": "154",
"_score": 1.0,
"_source": {
"firstname": "Alice",
"home_city": "Paia",
"home_address": "581 Pili Loko Street",
"home_zip": "00012",
"contact_id": "154",
"email": "aHernes@gmail.com",
"lastname": "Hernes",
"home_state": "Hawaii",
"cell_phone": "8083829103"
}
}
]
}
}
我相信弹性会让你有点困惑。
3 个字母术语的模糊度为 1,因此您期望“Bob”返回就足够了。 但是,我假设您使用默认过滤器“小写”的标准分析器。
因此计算出的“Boc”和“bob”之间的 Levenshtein 距离是2 ,这就是它没有返回的原因。
尝试小写输入术语,我打赌会返回“Bob”。
// no results
{
"query": {
"fuzzy" : { "firstname" : "Boc" }
}
}
// "Bob" returned
{
"query": {
"fuzzy" : { "firstname" : "boc" }
}
}
这有意义吗?
关于您的代码:
public void searchResults(@PathParam("index_name") String index_name) throws IOException {
RestHighLevelClient client = createHighLevelRestClient();
int numberOfSearchHitsToReturn = 100; // defaults to 10
SearchSourceBuilder sourceBuilder = new SearchSourceBuilder();
// "Boc".toLowerCase() or simply "boc"
sourceBuilder.query(QueryBuilders.fuzzyQuery("firstname", "Boc".toLowerCase()));
sourceBuilder.from(0);
sourceBuilder.size(numberOfSearchHitsToReturn);
sourceBuilder.timeout(new TimeValue(60, TimeUnit.SECONDS));
SearchRequest searchRequest = new SearchRequest(index_name).source(sourceBuilder);
SearchResponse searchResponse = client.search(searchRequest, RequestOptions.DEFAULT);
System.out.print(searchResponse);
client.close();
}
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