MYSQL查找每天的平均时间

Question

我有一个看起来像这样的表，叫做“victory_picker_picktask_scanactivity”

PickerID|ObjectScanned|      StartTime     |        EndTime     |
------------------------------------------------------------------
   2    |     Bin     |2020-02-17 03:46:58 | 2020-02-17 03:47:13  
   2    |     Bin     |2020-02-17 13:34:02 | 2020-02-17 13:34:27

我想找到每天的平均秒数

我正在使用此查询来获取某一天，但它被硬编码为我每天都想要的一天

SELECT AVG(TIMESTAMPDIFF(SECOND, `StartTime`, `EndTime`)) 
as time_in_seconds 
FROM `victory_picker_picktask_scanactivity` 

WHERE `victory_picker_picktask_scanactivity`.`EndTime` IS NOT NULL
AND `PickerID` = 2
AND  `EndTime` < '2020-02-18 00:00:01' 
AND `ObjectScanned` = 'Bin'

Answer 1

假设开始时间和结束时间在同一天：

SELECT DATE(StartTime), AVG(TIMESTAMPDIFF(SECOND, `StartTime`, `EndTime`)) 
as time_in_seconds 
FROM `victory_picker_picktask_scanactivity` 
WHERE `victory_picker_picktask_scanactivity`.`EndTime` IS NOT NULL
      `PickerID` = 2 AND
      `ObjectScanned` = 'Bin'
GROUP BY DATE(StartTime);

Answer 2

您还可以查看START_DATE和END_DATE比较

       SELECT AVG(TIMESTAMPDIFF(SECOND, `StartTime`, `EndTime`)) 
        as time_in_seconds 
       FROM `victory_picker_picktask_scanactivity` 

       WHERE `victory_picker_picktask_scanactivity`.`EndTime` IS NOT NULL
              AND `PickerID` = 2
              AND  date(`EndTime`) =date(`StartTime`) 
              AND `ObjectScanned` = 'Bin'