[英]MongoDB aggregation : Group by Category and sum up the amount
我的收藏中有以下结构(您不必介意状态):
{
"_id": {
"$oid": "5e6355e71b14ee00175698cb"
},
"finance": {
"expenditure": [
{
"status": true,
"_id": { "$oid": "5e63562d1b14ee00175698df" },
"amount": { "$numberInt": "100" },
"category": "Sport"
},
{
"status": true,
"_id": { "$oid": "5e6356491b14ee00175698e0" },
"amount": { "$numberInt": "200" },
"category": "Sport"
},
{
"status": true,
"_id": { "$oid": "5e63565b1b14ee00175698e1" },
"amount": { "$numberInt": "50" },
"category": "Outdoor"
},
{
"status": true,
"_id": { "$oid": "5e63566d1b14ee00175698e2" },
"amount": { "$numberInt": "400" },
"category": "Outdoor"
}
]
}
}
我以前的命令是这样的:
User.aggregate([
{ $match: {_id: req.user._id} },
{ $unwind: '$finance.expenditure' },
{ $match: {'finance.expenditure.status': true} },
{ $sort: {'finance.expenditure.currentdate': -1} },
{
$group: {
_id: '$_id',
expenditure: { $push: '$finance.expenditure' }
}
}
])
有了这个,我就可以收回每一笔支出。
但是现在我想按类别对支出进行分组,并总结出他们所在组的每项支出的金额。
所以它应该是这样的:
{ "amount": 300 }, "category": "Sport" },
{ "amount": 450 }, "category": "Outdoor" }
谢谢你的帮助
而不是在类别字段和总金额字段上的_id
字段组上分组:
db.collection.aggregate([
{ $match: {_id: req.user._id}},
{
$unwind: "$finance.expenditure"
},
{
$match: {
"finance.expenditure.status": true
}
},
{
$sort: {
"finance.expenditure.currentdate": -1
}
},
{
$group: {
_id: "$finance.expenditure.category",
amount: {
$sum: "$finance.expenditure.amount"
}
}
},
{
$project: {
_id: 0,
category: "$_id",
amount: 1
}
}
])
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